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Naddika [18.5K]
2 years ago
11

3.00 m^3 of water is at 20.0°C.

Physics
1 answer:
krok68 [10]2 years ago
6 0

Answer:

9m^3

Explanation:

Given data

volume  v1=  3m^3

volume  v2=  ???

Temperature T1= 20.0°C.

Temperature T2= 60.0°C.

Applying the relation for temperature and volume

V1/T1= V2/T2

substitute

3/20= V2/60

3*60= V2*20

180= 20*V2

180/20= V2

V2= 9m^3

Hence the final volume is 9m^3

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An ice-making machine inside a refrigerator operates in a Carnot cycle. It takes heat from liquid water at 0.0 ∘C and rejects he
Agata [3.3K]

Answer:

2.36 x 10^6 J

Explanation:

Tc = 0°C = 273 K

TH = 22.5°C = 295.5 K

Qc = heat used to melt the ice

mass of ice, m = 85.7 Kg

Latent heat of fusion, L = 3.34 x 10^5 J/kg

Let Energy supplied is E which is equal to the work done

Qc = m x L = 85.7 x 3.34 x 10^5 =  286.24 x 10^5 J

Use the Carnot's equation

\frac{Q_{H}}{Q_{c}}=\frac{T_{H}}{T_{c}}

Q_{H}=286.24\times 10^{5}\times \frac{295.5}{273}

QH = 309.8 x 10^5 J

W = QH - Qc

W = (309.8 - 286.24) x 10^5

W = 23.56 x 10^5 J

W = 2.36 x 10^6 J

Thus, the energy supplied is 2.36 x 10^6 J.

8 0
3 years ago
44.2 cm + 0.123 cm = cm
trapecia [35]
The answer is 44.323 cm
3 0
3 years ago
Read 2 more answers
What additional information do you need to prove ∆ABC ≅ ∆DEF by the SAS Postulate?
miv72 [106K]

Answer:

Option A

You need a Angle C congruent to angle F

Explanation:

EX) Side angle Side = sas

6 0
3 years ago
How do you solving kinematic equations for horizontal projectiles?
daser333 [38]
See projectiles are very simple unless you understand its core concepts....projectile is nothing just mixture of upward motion and horizontal motion....
THE KEY IS FORGET THE NAME PROJECTILE...ITS JUST HORIZONTAL MOTION + VERTICAL MOTION

7 0
2 years ago
A race car has a centripetal acceleration of 13.33 m/s^2 as it goes around a curve. if the curve is a circle with a radius 30 m
anzhelika [568]

Answer:

The speed of the car, v = 19.997 m/s

Explanation:

Given,

The centripetal acceleration of the car, a = 13.33 m/s²

The radius of the curve, r = 30 m

The centripetal force acting on the car is given by the formula

                                   F = mv²/r

Where    v²/r is the acceleration component of the force

                                       a = v²/r

Substituting the values in the above equation

                                        13.33 = v²/30

                                         v² = 13.33 x 30

                                         v² = 399.9

                                         v = 19.997 m/s

Hence, the speed of the car, v = 19.997 m/s

3 0
2 years ago
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