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STatiana [176]
4 years ago
9

Help!!! Which expressions are equivalent to 4^3 x 4^-5?

Mathematics
1 answer:
SashulF [63]4 years ago
4 0
A, B, D, E, H, I, J

Those are the answers
You might be interested in
X+5/2 + x−3/3 =3 1/6
Nataly [62]
The answer is x=-1/2
3 0
4 years ago
Read 2 more answers
Select the correct answer from each drop-down menu.
dem82 [27]
I believe 1 is 3.8, b/c 1.9*2 is 3.8, and the difference between exponents makes 3 zeros, so 2000.
The second one is 40, I confirmed this by doing .0001 to replicate 10 to the negative 4th power
By doing 9.5*.0001*40, I got the 0.038 from 1
6 0
3 years ago
Read 2 more answers
A little girl counts using the fingers of her left hand as follows:
Vanyuwa [196]

Answer:

1 to 10 = Pointer Finger

1 to 100 = Ring Finger

1 to 1000 = Ring Finger

Step-by-step explanation:

Every time she counts 10 on her fingers starting from 1 it either lands on her Index Finger or Ring Finger in a pattern of starting first on her index finger for 10 then ending up on her Ring Finger for 20 and 30 the going back to her Index finger for 40 and 50 and so on. Using this you can figure out 100 and 1000.

3 0
3 years ago
Perfect square trinomial conditions
aev [14]

Step-by-step explanation:

step 1. an example of difference of squares (dos) is (x + y)(x - y) = x^2 - y^2.

step 2. dos must have only 2 square rootable terms and a "-" between them.

step 3. 196x^2 - 121y^2 = (14x + 11y)(14x - 11y) works!

step 4. 5x^2 - 245 = 5(x^2 - 49) = 5(x + 7)(x - 7) works!

step 5. 27w^5 - 75w = 3w(9w^4 - 25) = 3w(3w^2 + 5)(3w^2 - 5) works!

step 6. x^4 - 100y^2 = (x^2 - 10y)(x^2 + 10y) works!

4 0
3 years ago
Without using logarithm tables, find the value of x given that: 2log2/3 = 1/2logx - log 18 + log 16
sweet-ann [11.9K]

Answer:

x=\frac{1}{4}

Step-by-step explanation:

<u>Given:</u>

2log(\frac{2}{3})=\frac{1}{2}log(x)-log(18)+log(16)

<u>Use the Power Rule Law:</u>

log(\frac{2}{3}^2)=log(x^{1/2})+log(16)-log(18)

<u>Use the Quotient Rule Law:</u>

log(\frac{4}{9})=log(\sqrt{x})+log(\frac{16}{18})

<u>Use the Product Rule Law:</u>

log(\frac{4}{9})=log(\frac{16\sqrt{x}}{18})

<u>Simplify:</u>

log(\frac{4}{9})=log(\frac{8\sqrt{x}}{9})

\frac{4}{9}=\frac{8\sqrt{x}}{9}

4=8\sqrt{x}

\frac{4}{8}=\sqrt{x}

\frac{1}{2}=\sqrt{x}

\frac{1}{4}=x

5 0
2 years ago
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