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dybincka [34]
4 years ago
5

A geosynchronous satellite moves in a circular orbit around the Earth and completes one circle in the same time T during which t

he Earth completes one revolution around its own axis. The satellite has mass m and the Earth has mass M and radius R. In order to be geosynchronous, the satellite must be at a certain height h above the Earth’s surface. Derive an expression for h in terms of m, M. R, T and constants.
Physics
2 answers:
andreyandreev [35.5K]4 years ago
7 0

Answer:

Explanation:

The time period of geosynchronous satellite must be equal to T .

The radius of its orbit will be (  R+ h )

orbital velocity  V₀ =  \sqrt{\frac{GM}{( R+h)} }

Time period T = 2π( R + h ) / V₀

= 2π( R + h ) x \sqrt{\frac{( R+h)}{GM } }

\frac{T^\frac{2}{3}(GM)^\frac{1}{3}  }{(2\pi )^\frac{2}{3} } = R +h

h = \frac{T^\frac{2}{3}(GM)^\frac{1}{3}  }{(2\pi )^\frac{2}{3} } - R.

tatyana61 [14]4 years ago
7 0

Answer:

The expression is:

h=\sqrt[3]{\frac{GMT^{2} }{4\pi ^{2} } } -R

Explanation:

please, the solution is in the attached Word file

Download docx
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Vinvika [58]
Answer is a. 180 degree
7 0
3 years ago
Potassium is a crucial element for the healthy operation of the human body. Potassium occurs naturally in our environment and th
Mariulka [41]

Answer:

a) 0.0288 grams

b) 2.6*10^{-10} J/kg

Explanation:

Given that:

A typical human  body contains about 3.0 grams of Potassium per kilogram of body mass

The abundance  for the three isotopes are:

Potassium-39, Potassium-40, and Potassium-41 with abundances are 93.26%, 0.012% and 6.728% respectively.

a)

Thus; a person with a mass of 80 kg will posses = 80 × 3 = 240 grams of potassium.

However, the amount of potassium that is present in such person is :

0.012% × 240 grams

= 0.012/100 × 240 grams

= 0.0288 grams

b)

the effective dose (in Sieverts) per year due to Potassium-40 in an 80- kg body is calculate as follows:

First the Dose in (Gy) = \frac{energy \ absorbed }{mass \ of \ the \ body}

= \frac{1.10*10^6*1.6*10^{-14}}{80}

= 2.2*10^{-10} \ J/kg

Effective dose (Sv) = RBE × Dose in Gy

Effective dose (Sv) =  1.2  *2.2*10^{-10} \ J/kg

Effective dose (Sv) = 2.6*10^{-10} J/kg

 

5 0
4 years ago
Sally runs 10,000 meter race at an average speed of 3.5m/s what does average speed mean
aleksandr82 [10.1K]

Answer:

The average speed of 3.5 m/s means that it takes Sally approximately 47.619 minutes to run 10,000 meters

Explanation:

Average speed is a scalar quantity that is given by dividing the total distance moved or traveled by an object by the time that it takes the object during the motion

The average peed indicates the rate at which the object makes a given amount of journey distance given that the journey is completed with varying speeds

With the knowledge of the average speed and the distance covered, the time for completion of the journey can be found as follows;

Average \ speed , \overline v = \dfrac{\Delta x}{\Delta t}

Where

\overline v = Average speed of the object = 3.5 m/s

Δt = The time it takes the Sally to run 10,000 meters

Δx = The total distance Sally runs = 10,000 meters

Therefore;

\Delta t = \dfrac{\Delta x}{ \overline v} = \dfrac{10,000 \ m}{3.5 \ m/s}  = \dfrac{20,000}{7} \ s \approx 2,857.143 \ s

The time it takes the Sally to run 10,000 meters= Δt = 20,000/7 seconds ≈ 2,857.143 seconds

20,000/7 seconds ≈ 47.619 minutes

Therefore, the average speed of 3.5 m/s means that the time it takes the Sally to run 10,000 meters ≈ 47.619 minutes

5 0
3 years ago
What is the resistance In a circuit that carries 0.75A current when powered by a 1.5 V battery?
Anit [1.1K]

Answer:

2.0 Ω

Explanation:

V = IR

1.5 V = (0.75 A) R

R = 2.0 Ω

4 0
4 years ago
2) Why do satelites not<br> Fall while revolving<br> around the earth?
MrRissso [65]

Answer:

Because they are moving to fast for Earth's gravity to pull it down.

7 0
3 years ago
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