The acceleration of the boat is 
(eastward)
Explanation:
We can solve this problem by using Newton's second law, which states that:
F = ma (1)
where
F is the net force on a body
m is its mass
a is its acceleration
First of all, we have to find the net force acting on the boat. We have:
- The force of the motor, 100 N eastward
- The force of the air resistance, 60 N westward
So the net force is:
F = 100 N - 60 N = 40 N (eastward)
Now we can apply eq.(1), using:
F = 40 N
m = 20 kg (mass of the boat)
and solving for a, we find the acceleration:
And the direction is the same as the net force (eastward).
Learn more about acceleration and Newton laws of motion:
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Answer:
P = 75 W
Explanation:
given,
Distance, L = 8 m
Force,F = 150 N
Time, t = 16 s
Work by the climber
Work done = Force x displacement
W = F. L
W = 150 x 8
W = 1200 J
We know,
P = 75 W
Hence, Power climber is using to climb is equal to 75 W.
Answer: the 30gram will hit the ground first
Explanation:the 30gram bullet will hit the ground first because it is fired
Answer:
C = 17 i^ - 7 j^ + 16 k^
, | C| = 24.37
Explanation:
To work the vactor component method, we add the sum in each axis
C = A + B = (Aₓ + Bₓ) i ^ + (
+ 
) i ^ + (
+ 
) k ^
Cₓ = 12+ 5 = 17
= -37 +30 = -7
= 58 -42 = 16
Resulting vector
C = 17 i ^ - 7j ^ + 16k ^
The mangitude of the vector is
| C | = √ c²
| C | = √( 17² + 7² + 16²)
| C| = 24.37
Answer: Rn :)))) no explanation needed
