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Zielflug [23.3K]
3 years ago
13

Drag each pressure unit with the corresponding number to describe standard atmospheric pressure.

Chemistry
1 answer:
saw5 [17]3 years ago
8 0

Answer:

The answer to your question is:

                                                    Psi = 14.7

                                                     Atm = 1

                                                     kPa = 101.3          

Explanation:

Psi: means "Pounds of force per Square Inch of area " an is a unit of pressure.

Atm: means atmosphere and is a unit of pressure defined as 101325 Pa.

kPa: is defined as the force of 1 Newton applied over one square meter.

      ( 101325 Pa = 101.3 kPa)

Then

        Psi = 14.7

         Atm = 1

         kPa = 101.3          

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When pcl5 solidifies it forms pcl4 cations and pcl6–anions. according to valence bond theory, what hybrid orbitals are used by p
SSSSS [86.1K]

When pcl5 solidifies it forms pcl4 cations and pcl6–anions. according to valence bond theory, hybrid orbitals that  are used by phosphorus in the pcl4 cations are one orbital of s and three orbital of p as it is sp³hydridised.

<h3>What is sp³ hybridization?</h3>

Hybridization is a process or system which specifies the shape and geometry of any element or molecule with bond angles too.

The pcl4 cation is sp³ hybridized because of the phosphorus behave as a central atom here and the 4 chloride molecules are attached with the p- orbitals to the phosphorus molecule.

Therefore, pcl4 cation  is sp³ hybridized.

Learn more about sp³ hybridization, here :

brainly.com/question/13062274

#SPJ4

5 0
2 years ago
1. An object was carefully weighed on three different balances. Each balance was zeroed
Hoochie [10]

Answer:

10.335

Explanation:

An object was carefully weighed on three different balances

Each of these balances were zeroed before weighing

The masses that were weighed are as follows

10.35 g , 10.355 g, 10.30 g

Therefore the average value of these measurements can be calculated as follows

The total number of mass is 3

= 10.30 + 10.355 + 10.30/3

= 31,005/3

= 10.335

Hence the average value of these measurements is 10.335

7 0
3 years ago
How many Red data lists were compiled for South Africa?​
e-lub [12.9K]

Answer:

Don't know if I know itat all

Explanation:

what is red data list

6 0
3 years ago
What is the density of a 805 g sample of pure silicon with a volume of 2.3 cm3?
MAVERICK [17]
The density of it would be 57. Do the math and apply the formula to it and you would get this answer.
3 0
3 years ago
What is the density of air at 75 F and latm pressure? Express in lbm/ft3 and kg/m3
ser-zykov [4K]

Answer : The density of air in lbm/ft^3 and kg/m^3 is, 0.0743lbm/ft^3 and 1.19kg/m^3 respectively.

Explanation :

PV=nRT\\\\PV=\frac{m}{M}RT\\\\P=\frac{m}{V}\frac{RT}{M}\\\\P=\rho \frac{RT}{M}\\\\\rho=\frac{PM}{RT}

where,

P = pressure of air = 1 atm

V = volume of air

T = temperature of air = 297 K

The conversion used for the temperature from Fahrenheit to degree Celsius is:

^oC=(^oF-32)\times \frac{5}{9}

^oC=(75-32)\times \frac{5}{9}=24^oC

The conversion used for the temperature from degree Celsius to Kelvin is:

K=273+^oC

K=273+24=297K

n = number of moles

m = mass of air

M = average molar mass of air = 28.97 g/mole

\rho = density of air = ?

R = gas constant = 0.0821 L.atm/mol.K

Now put all the given values in the above formula, we get:

\rho=\frac{PM}{RT}

\rho=\frac{(1atm)\times (28.97g/mole)}{(0.0821L.atm/mol.K)\times (297K)}

\rho=1.19g/L

Now we have to calculate density in lbm/ft^3.

Conversion used :

1g/L=0.0624lbm/ft^3

So,

1.19g/L=\frac{1.19g/L}{1g/L}\times 0.0624lbm/ft^3=0.0743lbm/ft^3

The density of air in lbm/ft^3 is, 0.0743lbm/ft^3

Now we have to calculate density in kg/m^3.

Conversion used :

1g/L=1kg/m^3

So,

1.19g/L=1.19kg/m^3

The density of air in kg/m^3 is, 1.19kg/m^3

8 0
3 years ago
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