Answer:
The value of the equilibrium constant Kc is 5.45
Explanation:
The "Law of Mass Action" states:
"For a reversible reaction in chemical equilibrium at a given temperature, it is true that the product of the concentrations of the products raised to the stoichiometric coefficients divided by the product of the concentrations of the reactants raised to their stoichiometric coefficients is a constant."
This constant was called the equilibrium constant. For a reaction:
aA + bB ⇄ cC + dD
the equilibrium constant Kc is:
![Kc=\frac{[C]^{c} *[D]^{d} }{[A]^{a} *[B]^{b} }](https://tex.z-dn.net/?f=Kc%3D%5Cfrac%7B%5BC%5D%5E%7Bc%7D%20%2A%5BD%5D%5E%7Bd%7D%20%7D%7B%5BA%5D%5E%7Ba%7D%20%2A%5BB%5D%5E%7Bb%7D%20%7D)
In this case, the balanced reaction is:
2 H₂S → 2 H₂ + S₂
So, the equilibrium constant Kc is:
![Kc=\frac{[H_{2} ]^{2} *[S_{2} ] }{[H_{2} S]^{2} }](https://tex.z-dn.net/?f=Kc%3D%5Cfrac%7B%5BH_%7B2%7D%20%5D%5E%7B2%7D%20%2A%5BS_%7B2%7D%20%5D%20%7D%7B%5BH_%7B2%7D%20S%5D%5E%7B2%7D%20%20%7D)
The equilibrium concentrations are
- [H₂S] =0.25 M
- [H₂]= 0.88 M
- [S₂]= 0.44M
Replacing in the definition of equilibrium constant:

Solving:
Kc= 5.45
<u><em>The value of the equilibrium constant Kc is 5.45</em></u>
<u><em></em></u>
Answer:
(2) Boiling point order: Methanol (highest) > Methanal > Methane (weakest)
(3) Boiling point of alcohol will be higher than ester molecules
Explanation:
(2) Methane is a non-polar molecule. Hence only weakest van der waal inter molecular force is present between methane molecules.
Methanal is polar molecule due to presence of polar aldehyde group. hence weaker dipole-dipole inter molecular force is present between methanal molecules.
Methanol is a polar protic molecule. Hence strongest H-bonding force act between methanol molecules.
The stronger the inter molecular force, the higher will be boiling point.
Boiling point order: Methanol (highest) > Methanal > Methane (weakest)
(3) An alcohol is a polar protic molecule. Hence strongest H-bonding force exist between alcohol molecules.
An ester is polar molecule. Therefore weaker dipole-dipole inter molecular force is present between ester molecules.
So boiling point of alcohol will be higher than ester molecules.
<span>Supporting combustion is a chemical property because it involves a chemical reaction that can only be reversed with another chemical reaction.</span>