Answer:
AB = 10, BC = 10
Step-by-step explanation:
AB = length of segment AB = sqrt( (-3-5)^2 + (-4-2)^2 ) = sqrt( 64 + 36) = sqrt(100) = 10
BC = sqrt( (5-11)^2 + (2-(-6))^2 ) = sqrt( 36 + 64 ) = sqrt( 100 ) = 10
The area will be half the product of the lengths of AB and CD.
|AB| = √((6-1)² +(-2-3)²) = 5√2
|CD| = √((5-2)² +(5-2)²) = 3√2
Area = (1/2)*(5√2)*(3√2) = (1/2)*(15*2) = 15
The appropriate choice is ...
D: 15 square units
For one of the triangular sides, 2.6 x 4 = 10.4 divided by 2 = 5.2
Other triangle; 2.6 x 3 = 7.8 /2 = 3.9
Rectangular side in front; 6.5 x 3 = 19.5
Back; 6.5 x 4 = 26
Base; 6.5 x 2.6 = 16.9
Answer: For the surface area it is 74.6 (SUPER SORRY IF THIS ISNT RIGHT OMG)
we know that
If 
is a factor of the function 
then
is a root of the function f(x)
therefore
For the value of the function must be zero
Verify
Substitute the value of in the function
therefore
<u>the answer is</u>
Yes, is a factor of the function f(x)
Answer:
0
Step-by-step explanation:
Find the following limit:
lim_(x->∞) 3^(-x) n
Applying the quotient rule, write lim_(x->∞) n 3^(-x) as (lim_(x->∞) n)/(lim_(x->∞) 3^x):
n/(lim_(x->∞) 3^x)
Using the fact that 3^x is a continuous function of x, write lim_(x->∞) 3^x as 3^(lim_(x->∞) x):
n/3^(lim_(x->∞) x)
lim_(x->∞) x = ∞:
n/3^∞
n/3^∞ = 0:
Answer: 0
