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devlian [24]
4 years ago
3

A weather balloon is released into the atmosphere. You know the initial volume, temperature, and air pressure. What information

will you need to predict its volume when it reaches its final altitude? Which law would you use to calculate this volume?
Chemistry
1 answer:
Dominik [7]4 years ago
3 0

Answer:

You will need the final temperature and the final pressure.

You would use the general gas equation.

Explanation:

The general gas equation is

\frac{P1xV1}{T1} = \frac{P2xV2}{T2}

Where <em>P</em> is the pressure,<em> V</em> is the volume, <em>T </em>is the temperature, <em>1</em> refers to the initial state, and <em>2</em> refers to the final state. So, knowing the final pressure and temperature would be possible to calculate the final volume.

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Please help me with this.
zlopas [31]

Answer A: Connect a wire coil to an ammeter. Move a bar magnet into and out of the wire coil as you observe the ammeter.

6 0
3 years ago
44Given the equation representing a reaction at equilibrium :2SO2(g) + O2(g) ==&gt; 2SO3(g) + heat
kotykmax [81]
(2) Adding more O2(g) would shift the equilibrium to the right because a higher concentration of oxygen is offered than its initial position, therefore more products have to be yielded to maintain equilibrium.
4 0
3 years ago
Which of the following statements about 13C NMR is not true?A. In 13C proton-decoupled NMR spectra, all peaks are singlets.B. 13
adoni [48]

Answer: .B. 13C NMR spectra display peaks for only carbons that bear hydrogen atoms.

Explanation:

The statements that are true about 13C NMR are:

A. In 13C proton-decoupled NMR spectra, all peaks are singlets.

C 13C NMR chemical shifts occur over a greater range than 1H NMR chemical shifts.

D. 13C NMR easily differentiates between the different hybridized carbons (sp3, sp2, and sp hybridized carbons).organic-chemistry

Therefore, the option that isn't true is option B. "13C NMR spectra display peaks for only carbons that bear hydrogen atoms". This is false because 13C NMR will show every peak in the spectrum and it doesn't matter if it's only carbons that bear hydrogen atoms as everything will be shown.

4 0
3 years ago
For the reaction, A(g) + B(g) =&gt; AB(g), the rate is 0.385 mol/L.s when the initial concentrations of both A and B are 2.00 mo
Tanya [424]

Answer : The rate for a reaction will be 0.14Ms^{-1}

Explanation :

The balanced equations will be:

A(g)+B(g)\rightarrow AB(g)

In this reaction, A and B are the reactants.

The rate law expression for the reaction is:

\text{Rate}=k[A]^2[B]^1

or,

\text{Rate}=k[A]^2[B]

Now, calculating the value of 'k' by using any expression.

\text{Rate}=k[A]^2[B]

0.385=k(2.00)^2(2.00)

k=0.0481M^{-2}s^{-1}

Now we have to calculate the initial rate for a reaction that starts with 1.48 M of reagent A and 1.32 M of reagents B.

\text{Rate}=k[A]^2[B]^0[C]^1

\text{Rate}=(0.0481)\times (1.48)^2(1.32)^1

\text{Rate}=0.14Ms^{-1}

Therefore, the rate for a reaction will be 0.14Ms^{-1}

7 0
4 years ago
Suppose that you have a 60.0% solution of NaOH. How many milliliters of water must be added to 30.0 mL of this solution to prepa
defon

Answer:

  • <u>21.4 ml (second choice)</u>

Explanation:

<u>1) Data:</u>

a) C₁ = 60.0% (initial solution)

b) V₁ = 30.0 ml (initial solution)

c) C₂ = 0% (pure water)

d) V₂ = ? (pure water)

e) C₃ = 35.0% (final concentration)

<u>2) Formula:</u>

  • C₁V₁ + C₂V₂ = C₃V₃
  • V₁ + V₂ = V₃ (assuming volume addtivity)

<u>3) Solution:</u>

<u />

a) Substitute values in the first formula:

  • 60.0% × 30 ml + 0 = 35% (30 ml + V₂)

b) Solve the equation (units are supressed just to manipulate the terms)

  • 18 = 10.5 + 0.35V₂

  • 0.35V₂ = 18 - 10.5 = 7.5

  • V₂ = 7.5 / 0.35 = 21.4 ml ← answer    
3 0
4 years ago
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