Answer A: Connect a wire coil to an ammeter. Move a bar magnet into and out of the wire coil as you observe the ammeter.
(2) Adding more O2(g) would shift the equilibrium to the right because a higher concentration of oxygen is offered than its initial position, therefore more products have to be yielded to maintain equilibrium.
Answer: .B. 13C NMR spectra display peaks for only carbons that bear hydrogen atoms.
Explanation:
The statements that are true about 13C NMR are:
A. In 13C proton-decoupled NMR spectra, all peaks are singlets.
C 13C NMR chemical shifts occur over a greater range than 1H NMR chemical shifts.
D. 13C NMR easily differentiates between the different hybridized carbons (sp3, sp2, and sp hybridized carbons).organic-chemistry
Therefore, the option that isn't true is option B. "13C NMR spectra display peaks for only carbons that bear hydrogen atoms". This is false because 13C NMR will show every peak in the spectrum and it doesn't matter if it's only carbons that bear hydrogen atoms as everything will be shown.
Answer : The rate for a reaction will be 
Explanation :
The balanced equations will be:

In this reaction,
and
are the reactants.
The rate law expression for the reaction is:
![\text{Rate}=k[A]^2[B]^1](https://tex.z-dn.net/?f=%5Ctext%7BRate%7D%3Dk%5BA%5D%5E2%5BB%5D%5E1)
or,
![\text{Rate}=k[A]^2[B]](https://tex.z-dn.net/?f=%5Ctext%7BRate%7D%3Dk%5BA%5D%5E2%5BB%5D)
Now, calculating the value of 'k' by using any expression.
![\text{Rate}=k[A]^2[B]](https://tex.z-dn.net/?f=%5Ctext%7BRate%7D%3Dk%5BA%5D%5E2%5BB%5D)


Now we have to calculate the initial rate for a reaction that starts with 1.48 M of reagent A and 1.32 M of reagents B.
![\text{Rate}=k[A]^2[B]^0[C]^1](https://tex.z-dn.net/?f=%5Ctext%7BRate%7D%3Dk%5BA%5D%5E2%5BB%5D%5E0%5BC%5D%5E1)


Therefore, the rate for a reaction will be 
Answer:
- <u>21.4 ml (second choice)</u>
Explanation:
<u>1) Data:</u>
a) C₁ = 60.0% (initial solution)
b) V₁ = 30.0 ml (initial solution)
c) C₂ = 0% (pure water)
d) V₂ = ? (pure water)
e) C₃ = 35.0% (final concentration)
<u>2) Formula:</u>
- C₁V₁ + C₂V₂ = C₃V₃
- V₁ + V₂ = V₃ (assuming volume addtivity)
<u>3) Solution:</u>
<u />
a) Substitute values in the first formula:
- 60.0% × 30 ml + 0 = 35% (30 ml + V₂)
b) Solve the equation (units are supressed just to manipulate the terms)
- V₂ = 7.5 / 0.35 = 21.4 ml ← answer