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serg [7]
3 years ago
15

Which represents the self-ionization of water at 25°C? H2O + H2O 2H2 + O2 H2O + H2O H2O2 + H2 H2O + H2O 4H+ + 2O2- H2O + H2O H3O

+ + OH-
Chemistry
2 answers:
artcher [175]3 years ago
8 0

Answer: Option (d) is the correct answer.

Explanation:

When molecules of same substance combine together to result in the formation of ions then this type of reaction is known as self-ionization.

For example, H_{2}O + H_{2}O \rightarrow H_{3}O^{+} + OH^{-}

So, here two molecules of water are combining and they result in the formation of hydronium ion (H_{3}O^{+}) and hydroxide ion (OH^{-}).

Hence, this reaction is a self-ionization reaction.

Vitek1552 [10]3 years ago
6 0
The fourth answer is correct 
H20 + H20  H30 + 0H-
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Calculate the mole fraction of each component in a solution with 6.87 g of sodium chloride (NaCl) dissolved in 65.2 g of water.
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Answer:

mole fraction of NaCl = 0.03145.

mole fraction of water = 0.9686.

Explanation:

  • Mole fraction is an expression of the concentration of a solution or mixture.
  • It is equal to the moles of one component divided by the total moles in the solution or mixture.
  • The summation of mole fraction of all mixture components = 1.

mole fraction of NaCl = (no. of moles of NaCl) / (total no. of moles).

<em>no. of moles of NaCl = mass/molar mass </em>= (6.87 g)/(58.44 g/mol) = 0.1176 mol.

<em>no. of moles of water = mass/molar mass</em> = (65.2 g)/(18.0 g/mol) = <em>3.622 mol.</em>

<em></em>

∴ mole fraction of NaCl = (no. of moles of NaCl) / (total no. of moles) = (0.1176 mol)/(0.1176 mol + 3.622 mol) = 0.03145.

<em>∵ mole fraction of NaCl + mole fraction of water = 1.0.</em>

∴ mole fraction of water = 1.0 - mole fraction of NaCl = 1.0 - 0.03145 = 0.9686.

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Under the vander waals forces of attraction we have what is known as the London dispersion forces. This force of attraction is a very weak and it is commonly found in the atoms of noble gases.

The intermolecular force of attraction in which we are talking about that is london dispersion forces is formed as a result of the formation of non-polar dipoles which are not permanent.

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