Let's say x is longest side, y is shortest side and z is the other side. So we have some equations such that
(by the first sentence)
(by the second sentence)
(by the third sentence)
By the second equation, we have
and if we use it in the first equation, then
. So
Since
, if we use it in the third equation the we have
then
Therefore
Given a group of
n object. We want to make a selection of
k objects out of the n object. This can be done in
C(n, k) many ways, where
,
where k!=1*2*3*...(k-1)*k
Thus, we can do the selection of 3 cd's out of 5, in C(5,3) many ways,
where
Answer: 10
What box plot are you talking about
Answer:
3x² + 30x
Step-by-step explanation:
width of a box = x units.
height of a box = 3 units.
length of a box = (x + 10) units.
Volume of the box = length × width × height
= (x + 10) * x * 3
= (x + 10) * 3x
= 3x² + 30x
Volume of the box = 3x² + 30x
Answer:
25 pi
Step-by-step explanation:
