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4 years ago

What is the difference between Concentration and Solubility

2 answers:

8 0

Concentration is the number of particles of a substance per unit volume.
Solubility is the abililty of a substance to dissolve in a solvent, for example the ability of salt to dissolve in water.

Mrac [35]4 years ago

3 0

Hi , the major difference between concentration and solubility is that solubility is measured in grams of solute per 100mL of solvent , while concentration is measured in grams of solute per 100mL of solution.

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Carbon-14 emits beta radiation and decays with a half life of 5730 years. Assume you start with 2.5x10^15 grams of Carbon-14, ho

saveliy_v [14]

The amount remaining at the end of 5 half-lives is 7.81×10¹³ g

From the question given above, the following data were obtained:

Half-life (t½) = 5730 years
Original amount (N₀) = 2.5×10¹⁵ g
Number of half-lives (n) = 5
Amount remaining (N) =?

The amount remaining can be obtained as follow:

N = 1/2ⁿ × N₀

N = 1/2⁵ × 2.5×10¹⁵

N = 1/32 × 2.5×10¹⁵

N = 0.03125 × 2.5×10¹⁵

N = 7.81×10¹³ g

Therefore, the amount remaining after 5 half-lives is 7.81×10¹³ g

Learn more about half-life: brainly.com/question/25783920

3 0

2 years ago

What is the IUPAC name of this compund?

mr_godi [17]

Answer:

3-ethyl-4-methyl Heptane

Explanation:

longest chain is straight .

we start assigning number from where we are close to the branch to this mean its from left hand side. and we saw two chain 1 is ethyl and other is methyl . In alphabetical order e comes first as compare to m so we write ethyl first after that methyl and than in last we write longest chain name with ane (bcz we only have single vonds).

4 0

3 years ago

Read 2 more answers

The gas release during a chemical reaction which causes fizzing known as?

IrinaVladis [17]

Answer:

Hey mate...

Explanation:

This is ur answer....

<h3>Effervescence</h3>

Effervescence is the escape of gas from an aqueous solution and the foaming or fizzing that results from that release.

Hope it helps!

Brainliest pls!

Follow me! ♧

8 0

3 years ago

Read 2 more answers

Aqueous sulfuric acid reacts with solid sodium hydroxide to produce aqueous sodium sulfate and liquid water . If of water is pro

sergeinik [125]

The question is incomplete, here is the complete question:

Aqueous sulfuric acid reacts with solid sodium hydroxide to produce aqueous sodium sulfate and liquid water. If 12.5 g of water is produced from the reaction of 72.6 g of sulfuric acid and 77.0 g of sodium hydroxide, calculate the percent yield of water. Be sure your answer has the correct number of significant digits in it.

Answer: The percent yield of water in the reaction is 46.85 %.

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

For NaOH:

Given mass of NaOH = 77.0 g

Molar mass of NaOH = 40 g/mol

Putting values in equation 1, we get:

$\text{Moles of NaOH}=\frac{77.0g}{40g/mol}=1.925mol$

For sulfuric acid:

Given mass of sulfuric acid = 72.6 g

Molar mass of sulfuric acid = 98 g/mol

Putting values in equation 1, we get:

$\text{Moles of sulfuric acid}=\frac{72.6g}{98g/mol}=0.741mol$

The chemical equation for the reaction of NaOH and sulfuric acid follows:

$H_2SO_4+2NaOH\rightarrow Na_2SO_4+2H_2O$

By Stoichiometry of the reaction:

1 mole of sulfuric acid reacts with 2 moles of NaOH

So, 0.741 moles of sulfuric acid will react with = $\frac{2}{1}\times 0.741=1.482mol$ of NaOH

As, given amount of NaOH is more than the required amount. So, it is considered as an excess reagent.

Thus, sulfuric acid is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

1 mole of sulfuric acid produces 2 moles of water

So, 0.741 moles of sulfuric acid will produce = $\frac{2}{1}\times 0.741=1.482moles$ of water

Now, calculating the mass of water from equation 1, we get:

Molar mass of water = 18 g/mol

Moles of water = 1.482 moles

Putting values in equation 1, we get:

$1.482mol=\frac{\text{Mass of water}}{18g/mol}\\\\\text{Mass of water}=(1.482mol\times 18g/mol)=26.68g$

To calculate the percentage yield of water, we use the equation:

$\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

Experimental yield of water = 12.5 g

Theoretical yield of water = 26.68 g

Putting values in above equation, we get:

$\%\text{ yield of water}=\frac{12.5g}{26.68g}\times 100\\\\\% \text{yield of water}=46.85\%$

Hence, the percent yield of water in the reaction is 46.85 %.

8 0

3 years ago

How many atoms of carbon are in 79.7 moles of carbon?

IgorLugansk [536]

Answer:

Hey, use this formula

Explanation:

1 mole of carbon has 6.022 × 1023 carbon atoms so what about 79.7 moles?

cross multiply and thats the answer

5 0

3 years ago