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taurus [48]
4 years ago
12

Determine the percent composition for each of the elements in magnesium nitrate, Mg(NO3)2. Please round to the nearest whole num

ber. First, find the molar mass of the WHOLE compound. Use whole numbers for the atomic mass. Mg(NO3)2
Chemistry
1 answer:
Verizon [17]4 years ago
8 0

Answer:

% Mg = 16.2 % ≈ 16 %

%N = 18.9 % ≈ 19 %

% O = 64.9 % ≈ 65 %

Explanation:

Step 1: Data given

Molar mass Mg(NO3)2 = 148 g/mol

Molar mass Mg = 24 g/mol

Molar mass N = 14 g/mol

Molar mass O = 16 g/mol

Step 2: Calculate the percent composition

% Mg = (24/148) *100%

% Mg = 16.2 % ≈ 16 %

% N = (2*14 / 148) * 100%

%N = 18.9 % ≈ 19 %

% O = (6*16/148) * 100%

% O = 64.9 % ≈ 65 %

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From a 2.875 g sample containing only iron, sand, and salt, 0.660 g of iron and 1.161 g of sand were separated and recovered. Wh
Serjik [45]

Answer:

36.66%

Explanation:

Step 1: Given data

  • Mass of iron: 0.660 g
  • Mass of sand: 1.161 g
  • Mass of the sample: 2.875 g
  • Mass of salt: ?

Step 2: Calculate the mass of salt

The mass of the sample is equal to the sum of the masses of the components.

m(sample) = m(iron) + m(sand) + m(salt)

m(salt) = m(sample) - m(iron) - m(sand)

m(salt) = 2.875 g - 0.660 g - 1.161 g

m(salt) = 1.054 g

Step 3: Calculate the percent of salt in the sample

We will use the following expression.

%(salt) = m(salt) / m(sample) × 100%

%(salt) = 1.054 g / 2.875 g × 100% = 36.66%

7 0
3 years ago
What is in an inorganic molecule?
valentinak56 [21]
Inorganic molecules are composed of other elements. They can contain hydrogen or carbon, but if they have both, they are organic.
6 0
3 years ago
Based on the following chemical equation how many hydrogen atoms are present in the products side?
e-lub [12.9K]

Answer:

the answer is 6

Explanation:

there is 3 hydrogen molecules in NH3 and there's 2 molecules of NH3 so in total, there are 6 hydrogen molecules on the products side.

8 0
3 years ago
A sample compound contains 5.723g Ag, 0.852g S and 1.695g O. Determine its empirical formula.
Lubov Fominskaja [6]

Answer:

Ag_2SO_4

Explanation:

Formula for the calculation of no. of Mol is as follows:

mol=\frac{mass\ (g)}{molecular\ mass}

Molecular mass of Ag = 107.87 g/mol

Amount of Ag = 5.723 g

mol\ of\ Ag=\frac{5.723\ g}{107.87\ g/mol} =0.05305\ mol

Molecular mass of S = 32 g/mol

Amount of S = 0.852 g

mol\ of\ S=\frac{0.852\ g}{32\ g/mol} =0.02657\ mol

Molecular mass of O = 16 g/mol

Amount of O = 1.695 g

mol\ of\ O=\frac{1.695\ g}{16\ g/mol} =0.10594\ mol

In order to get integer value, divide mol by smallest no.

Therefore, divide by 0.02657

Ag, \frac{0.05305}{0.02657} \approx 2

S, \frac{0.02657}{0.02657} \approx 1

O, \frac{0.10594}{0.02657} \approx 4

Therefore, empirical formula of the compound = Ag_2SO_4

7 0
4 years ago
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'The use of fertillizers only increases air pollution." What is wrong with this statement.
Alex787 [66]

Answer:

doesnt increase air pollution. fertilizers leak into the waters when it rains

3 0
4 years ago
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