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3 years ago

A solution of silver chlorate reacts with a solution of lithium iodide.

Chemistry

1 answer:

Anettt [7]3 years ago

7 0

Answer: $Ag^+(aq)+I^-(aq)\rightarrow AgI(s)$

Explanation:

A double displacement reaction is one in which exchange of ions take place. The salts which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) after their chemical formulas.

Spectator ions are defined as the ions which does not get involved in a chemical equation or they are ions which are found on both the sides of the chemical reaction present in ionic form.

The given chemical equation is:

$AgClO_3(aq)+LiI(aq)\rightarrow AgI(s)+LiClO_3(aq)$

The complete ionic equation is:

$Ag^+(aq)+ClO_3^-(aq)+Li^+(aq)+I^-(aq)\rightarrow AgI(s)+Li^+(aq)+ClO_3^-(aq)$

The ions which are present on both the sides of the equation are lithium and chlorate ions. and hence are not involved in net ionic equation.

Thus the net ionic equation is:

$Ag^+(aq)+I^-(aq)\rightarrow AgI(s)$

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An object has a mass of 0.0124kg and a volume of 1893mm3. What is its density in grams per cubic centimeter?

anyanavicka [17]

Answer:

6.25×10⁻⁶ g / cm³

Explanation:

Density is the relation between mass and volume as this formula shows.

Density of a compound = Mass of the compound / Volume of compound

In the values, we were given:

0.0124 kg / 1983 mm³ = 6.25×10⁻⁶ kg/mm³

This number means that in a volume of 1 mm³ of compound, the mass of it occupies 6.25×10⁻⁶ kg. Let's make a rule of three:

1 cm³ = 1×10⁻³ mm³

In 1 mm³ we have 6.25×10⁻⁶ kg of compound

So in 1×10⁻³ mm³ we would have (1×10⁻³ mm³ . 6.25×10⁻⁶ kg) / 1 mm³ =

6.25×10⁻⁹ kg

Now let's convert the kg to g.

1 kg = 1000 g

6.25×10⁻⁹ kg . 1000 = 6.25×10⁻⁶ g

Finally density is : 6.25×10⁻⁶ g / cm³

5 0

3 years ago

What is a substance which allows the red blood cells to carry oxygen and iron.

bogdanovich [222]

The answer is hemoglobin. The substance which allows the red blood cells to carry oxygen and iron is called hemoglobin. It is a protein containing iron. Its main function is to carry oxygen to all the parts of the body.

8 0

3 years ago

The following questions are about ethyl bromide,n-propyl bromide, isopropyl bromide,t-butyl bromide, & neopentyl bromide

mrs_skeptik [129]

Answer:

a) Watch the attaccment

b) Ethyl bromide is more reactive than n-propyl bromid, and this more than neopentyl bromide. Ethyl bromide has less steric hindrance than the others, to SN2 reactions.

c) t-butyl bromide is more reactive than isopropyl bromide, and this more than ethyl bromide. t-butyl bromide structure stabilize the carbocation, better than the others.

Explanation:

Speed of SN2 reactions depends on steric hindrance, the less hindrance, the most reaction speed, meaning more reactivity. Then, those linear structures are more reactive to SN2 reactions.

In the other hand, speed of SN1 reactions depends on the stability of the carbocation formed. Structure with ramifications can stabilize better the carbocation, these structures are more reactive to SN1 reactions.

Download pdf

7 0

3 years ago

PLEASE HELP ASAP!!! K+ has how many electrons? -19 -18 -20 -none of these

Y_Kistochka [10]

Answer:

Its 19.

Explanation:

K (potassium) has 19 electron according to the atomic number in the periodic table. The atomic number tells you the number of protons and electrons.

8 0

3 years ago

Please help, its urgent.

san4es73 [151]

Answer:

Mass of excess reactant left = 179.6 g

Limiting reactant = nitrogen

Mass of ammonia formed = 200.6 g

Explanation:

Given data:

Mass of nitrogen = 165.0 g

Mass of hydrogen = 215.0 g

Limiting reactant = ?

Mass of ammonia formed = ?

Mass of excess reactant left = ?

Solution:

Chemical equation:

N₂ + 3H₂ → 2NH₃

Number of moles of nitrogen:

Number of moles = mass/molar mass

Number of moles = 165.0 g/ 28 g/mol

Number of moles = 5.9 mol

Number of moles of hydrogen:

Number of moles = mass/molar mass

Number of moles = 215.0 g/ 2 g/mol

Number of moles = 107.5 mol

Now we will compare the moles of ammonia with both reactant.

H₂ : NH₃

3 : 2

107.5 : 2/3×107.5 = 71.7 mol

N₂ : NH₃

1 : 2

5.9 : 2/1×5.9 = 11.8 mol

Less number of moles of ammonia are formed by the nitrogen it will act as limiting reactant.

Mass of ammonia formed:

Mass = number of moles × molar mass

Mass = 11.8 mol × 17 g/mol

Mass = 200.6 g

Mass of hydrogen left:

We will compare the moles of hydrogen and nitrogen.

N₂ : H₂

1 : 3

5.9 : 3/1×5.9 = 17.7 mol

Out of 107.5 moles 17.7 moles of hydrogen react with nitrogen.

Number of moles left unreacted = 107.5 - 17.7 mol = 89.8 mol

Mass of hydrogen left:

Mass = number of moles × molar mass

Mass = 89.8 mol × 2 g/mol

Mass = 179.6 g

5 0

3 years ago