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3 years ago

A solution of silver chlorate reacts with a solution of lithium iodide.

Chemistry

1 answer:

Anettt [7]3 years ago

7 0

Answer: $Ag^+(aq)+I^-(aq)\rightarrow AgI(s)$

Explanation:

A double displacement reaction is one in which exchange of ions take place. The salts which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) after their chemical formulas.

Spectator ions are defined as the ions which does not get involved in a chemical equation or they are ions which are found on both the sides of the chemical reaction present in ionic form.

The given chemical equation is:

$AgClO_3(aq)+LiI(aq)\rightarrow AgI(s)+LiClO_3(aq)$

The complete ionic equation is:

$Ag^+(aq)+ClO_3^-(aq)+Li^+(aq)+I^-(aq)\rightarrow AgI(s)+Li^+(aq)+ClO_3^-(aq)$

The ions which are present on both the sides of the equation are lithium and chlorate ions. and hence are not involved in net ionic equation.

Thus the net ionic equation is:

$Ag^+(aq)+I^-(aq)\rightarrow AgI(s)$

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C6H12O6 + 6O2 + 38ADP + 38Pi => 6CO2 + 6H2O + 38ATP is the chemical equation for

Jobisdone [24]

Answer:

C6H12O6 + 6O2 + 38ADP + 38Pi => 6CO2 + 6H2O + 38ATP is the chemical equation for cellular respiration

Explanation:

Cellular respiration is the process by which cells breakdown glucose molecules to produce energy in the form of ATP molecules and release waste products such as carbon dioxide and water molecules. Cellular respiration involves a series of reaction pathways such as glycolysis, pyruvate oxidation, citric acid cycle and the oxidative phosphorylation pathway.

The first step of glycolysis breaks down a glucose molecule to release two pyruvate molecules.

In pyruvate oxidation, two molecules of pyruvate are oxidized to acetyl-CoA molecules.

In the citric acid cycle, the acetyl-CoA molecules are used to produce the electron carriers NADH and FADH2.

In the oxidative phosphorylation pathway, NADH and FADH2 donate their electrons to oxygen and ATP molecules are produced using the energy of electron transfer and proton-pumping.

The overall equation for cellular respiration is given as:

C6H12O6 + 6O2 + 38ADP + 38Pi => 6CO2 + 6H2O + 38ATP

3 0

3 years ago

Propane burns in oxygen to produce carbon dioxide and water what is the percent yeild

amid [387]

Answer:

The percentage yield is 78.2g

Explanation:

Given, mass of propane = 42.8 g , sufficient O2 percent yield = 61.0 % yield.

Reaction - C3H8(g)+5O2(g)------> 3CO2(g)+4H2O(g)

First we need to calculate the moles of propane

Moles of propane = $\frac{42.8}{44.096}$ g.mol-1

= 0.971 moles

So, moles of CO2 from the moles of propane

1 mole of C3H8(g) = 3 moles of CO2(g)

So, 0.971 moles of C3H8(g) = ?

= 2.913 moles of CO2

So theoretical yield = 2.913 moles $\times$ 44.0 g/mol

= 128.2 g

So, the actual mass of CO2 = percent yield $\times$ theoretical yield / 100 %

= 61.0 % $\times$ 128.2 g / 100 %

= 78.2 g

the mass of CO2 that can be produced if the reaction of 42.8 g of propane and sufficient oxygen has a 61.0 % yield is 78.2 g

4 0

3 years ago

can anyone help with this mole to mole/mole to grams question? any help would be greatly appreciated! Thanks!

goldenfox [79]

Answer:

Explanation:

a) 3.00 mol Cu x 2 mol Ag/ 1 mol Cu = 6 mol Ag

b) 3.00 mol Cu x 2 mol Ag/1 mol Cu x 107.87g Ag/ 1 mol Ag = 647.22g Ag

c) 3.00 mol Cu x 1 mol Cu(NO3)2/ 1 mol Cu = 3 mol Cu(NO3)2

d) 3.00 mol Cu x 1 mol Cu(NO3)2/ 1 mol Cu x 187.54g/ 1 mol Cu(NO3)2 =562.644g Cu(NO3)2

8 0

3 years ago

un estudiante introduce un corcho cuya densidad es 0.95 g/cm en cada uno de los liquidos que figura representa mejor la situacio

bagirrra123 [75]

Answer:

La respuesta correcta es la opción A.

Explicación:

La densidad del corcho es 0.95g / cm3 por lo que se hundirá en la solución de acetona porque el corcho es más denso que la solución de acetona mientras que por otro lado, el corcho flotará en otros dos líquidos porque la densidad del corcho es menor que en otros dos líquidos o, en otras palabras, los dos líquidos son más densos que el corcho, por eso el corcho flotará en estos dos líquidos.

4 0

3 years ago

How much energy must be removed from a 125 g sample of benzene (molar mass= 78.11 g/mol) at 425.0 K to liquify the sample and lo

riadik2000 [5.3K]

Answer : The energy removed must be, -67.7 kJ

Solution :

The process involved in this problem are :

$(1):C_6H_6(g)(425.0K)\rightarrow C_6H_6(g)(353.0K)\\\\(2):C_6H_6(g)(353.0K)\rightarrow C_6H_6(l)(353.0K)\\\\(3):C_6H_6(l)(353.0K)\rightarrow C_6H_6(l)(335.0K)$