All categories

2 years ago

A solution of silver chlorate reacts with a solution of lithium iodide.

Chemistry

1 answer:

Anettt [7]2 years ago

7 0

Answer: $Ag^+(aq)+I^-(aq)\rightarrow AgI(s)$

Explanation:

A double displacement reaction is one in which exchange of ions take place. The salts which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) after their chemical formulas.

Spectator ions are defined as the ions which does not get involved in a chemical equation or they are ions which are found on both the sides of the chemical reaction present in ionic form.

The given chemical equation is:

$AgClO_3(aq)+LiI(aq)\rightarrow AgI(s)+LiClO_3(aq)$

The complete ionic equation is:

$Ag^+(aq)+ClO_3^-(aq)+Li^+(aq)+I^-(aq)\rightarrow AgI(s)+Li^+(aq)+ClO_3^-(aq)$

The ions which are present on both the sides of the equation are lithium and chlorate ions. and hence are not involved in net ionic equation.

Thus the net ionic equation is:

$Ag^+(aq)+I^-(aq)\rightarrow AgI(s)$

You might be interested in

How many grams are there in 1.18 X 1026 atoms of iridium?

stealth61 [152]

You want to divide by avagadros number (6.22 x 10^23). This will cancel the atoms unit and give moles, moles of Iridium. Now you want to calculate the atomic mass of Iridium which is in units of grams per mole. Multiply these two numbers and the moles will cancel giving you grams.

Setting up a dimension analysis type of thing helps tremendously. See what you have to cancel in order to get what you want. We canceled the atoms, then we canceled the moles, and then we got grams.

4 0

2 years ago

An "empty" container is not really empty if it contains air. How may moles of nitrogen are in an "empty" two-liter cola bottle a

Lisa [10]

Answer:

1. 0.0637 moles of nitrogen.

2. The partial pressure of oxygen is 0.21 atm.

Explanation:

1. If we assume ideal behaviour, we can use the Law of ideal gases to find the moles of nitrogen, considering that air composition is mainly nitrogen (78%), oxygen (21%) and argon (1%):

$V_{N_2}=V_{T}\times 0.78=2L \times 0.78 =1.56 L\\PV=nRT\\n_{N_2}=\frac{PV}{RT}=\frac{1 atm\times 1.56 L}{0.0821\frac{atmL}{molK}\times 298 K}\\n_{N_2}= 0.0637 mol$

2. Now, in order to find he partial pressure of oxygen we need to find the total moles of air, and then the moles of oxygen. Then, we use these results to determine the molar fraction of oxygen, to multiply it with total pressure and get the partial pressure of oxygen as follows:

$n_{total}=\frac{1 atm \times 2L}{0.0821 \frac{atmL}{molK}298K}=0.0817 mol$

$V_{O_2}=2L \times 0.21 = 0.42 L\\n_{O_2}=\frac {1atm \times 0.42 L}{0.0821 \frac{atm L}{mol K}298 K}=0.0172 mol\\X_{O_2}=\frac{n_{O_2}}{n_{total}}=\frac{0.0172 mol}{0.0817 mol}= 0.21$

$P_{O_2}=X_{O_2} \times P = 1 atm \times 0.21 = 0.21 atm$

As you see, the molar fraction and volume fraction are the same because of the assumption of ideal behaviour.

3 0

2 years ago

Explain why hydrogen will form an ionic bond with fluorine but only forms covalent bonds with carbon

vaieri [72.5K]

A fluorine atom has seven valence electrons. ... Carbon will then have five valence electrons (its four and the one its sharing with fluorine). Covalently sharing two electrons is also known as a “single bond.” Carbon will have to form four single bonds with four different fluorine atoms to fill its octet.

4 0

2 years ago

Read 2 more answers

ACTUAL YIELD VS THEORETICAL YIELD?

lawyer [7]

Actual yield over theoretical yield, then multiply by 100

6 0

2 years ago

This element has 3 electrons in its Lewis dot structure and is in the 3p orbital section.

Lynna [10]

The answer is Al. If it is a main group element with 3 electrons in its Lewis dot structure, it must be in group 3A. If it is in the 3p orbital section, then it must be in period 3, since the p orbital is a valence orbital and the number that preceeds it is the principal quantum number. Therefore, your answer is the element in period 3 and group 3A, which is aluminum.

3 0

2 years ago