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Degger [83]
3 years ago
14

Which event is caused by gravity?​

Chemistry
1 answer:
Oxana [17]3 years ago
6 0

Answer:

C

Explanation:

Cause waves causes gravity to make higher waves

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Is water in a kettle boiling a chemical change
Luden [163]
When a kettle is boiling you are able to see the chemical reaction, from the stem leaving the kettle, so yes
Hope this helped  : )

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3 years ago
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At 273 k and 1.00 x 10^-2 atm, the density of a gas is 1.24 x 10^-5 g/cm3.
bija089 [108]

Root mean square velocity is the square root of the mean of the squares of speeds of different molecules. From kinetic theory of gas, the formula of root mean square velocity=C_{rms}= √\frac{3RT}{M}=√\frac{3PV}{M}=√\frac{3P}{d}, where, R= Universal gas constant, T= Absolute temperature, P= Pressure, V= Volume of gas, d= Density of gas.

Given,  T=273 K, P=1.00 x 10⁻² atm, d=1.24 x 10⁻⁵ g/cm³.

(a) Using the formula C_{rms}=√\frac{3P}{d}=√(3X1.00X10⁻²)/(1.24X10⁻⁵)=49.18

(b) Molar mass can be determined by using the formula C_{rms}=√{3RT}{M}

49.18=√\frac{3X8.314X273}{M}

49.18²=√(3X8.314X273)/M

M=\frac{3X8.314X273}{49.18^{2} }

M=1.67 ≅ 2

Molecular mass is 2.

(c) The gas is Helium (He) whose molecular mass is 2.

8 0
3 years ago
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Which must be the same when comparing 1 mol of oxygen gas, O2, with 1 mol of carbon monoxide gas, CO?
Julli [10]

Answer:

The number of molecules.

Explanation:

7 0
3 years ago
Pls this need this I am doing a test and I need to get this
Alexxx [7]

Answer:

nib7tttugi

Explanation:

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6 0
3 years ago
How much time would it take for 336 mg of copper to be plated at a current of 5.6 A ? Express your answer using two significant
schepotkina [342]

Answer:

1.8 × 10² s

Explanation:

Let's consider the reduction that occurs upon the electroplating of copper.

Cu²⁺(aq) + 2 e⁻ ⇒ Cu(s)

We will establish the following relationships:

  • 1 g = 1,000 mg
  • The molar mass of Cu is 63.55 g/mol
  • When 1 mole of Cu is deposited, 2 moles of electrons circulate.
  • The charge of 1 mole of electrons is 96,486 C (Faraday's constant).
  • 1 A = 1 C/s

The time  that it would take for 336 mg of copper to be plated at a current of 5.6 A is:

336mgCu \times \frac{1gCu}{1,000mgCu} \times \frac{1molCu}{63.55gCu} \times \frac{2mole^{-} }{1molCu} \times \frac{94,486C}{1mole^{-}} \times \frac{1s}{5.6C} = 1.8 \times 10^{2} s

3 0
3 years ago
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