Answer:
4NH₃(g) +3O₂(g) ⇒2N₂(g) +6H₂O(g)
Explanation:
Given :
A certain compound contains 4.0 g of calcium and 7.1 g of chlorine.
Its relative molecular mass is 111.
To Find :
Its empirical and molecular formulas.
Solution :
Moles of calcium , 
.
Moles of chlorine , 
.
The ratio calcium and chlorine is 1 : 2 .
So , the empirical formula is 
.
Now , molecular mass of is :
So , 
Therefore , the molecular formula is also .
Hence , this is the required solution .
C5H12(g) + 8 O2(g) = 5 CO2(g) + 6H2O(g)
molar ratio of H2O to O = 6:8
<span>we have 0.200 moles of H2O so we need 0.200 * 8/6 moles of O2 = 0.267 moles of O2
Therefore, there will be 0.267 moles of O2 gas required to yield 0.2 moles of H20.
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We are already given with the mass of the Xe and it is 5.08 g. We can calculate for the mass of the fluorine in the compound by subtracting the mass of xenon from the mass of the compound.
mass of Xenon (Xe) = 5.08 g
mass of Fluorine (F) = 9.49 g - 5.08 g = 4.41 g
Determine the number of moles of each of the element in the compound.
moles of Xenon (Xe) = (5.08 g)(1 mol Xe / 131.29 g of Xe) = 0.0387 mols of Xe
moles of Fluorine (F) = (4.41 g)(1 mol F/ 19 g of F) = 0.232 mols of F
The empirical formula is therefore,
Xe(0.0387)F(0.232)
Dividing the numerical coefficient by the lesser number.
<em> XeF₆</em>
To write a complete balanced reaction of a redox reaction, we need to know the half reactions of the molecules involved in the reaction and to balance these reactions. From, the problem statement ClO2- is oxidized to ClO4- so the half reaction would be:
(ClO)2- = (ClO)4-
To balance,
We first balance the elements except O and H in the reaction.
(ClO2)- = (ClO4)-
Then, we balance O by adding H2O and balance H by adding H+
(ClO2)- + 2H2O = (ClO4)- + 2H+
Then, we balance the charges by adding electrons,
(ClO2)- + 2H2O = (ClO4)- + 2H+ + e-
Then for Ag+ to Ag,
Ag+ = Ag
We just need to balance the charge,
Ag+ + e- = Ag
To determine the final equation, we add both half reactions:
(ClO2)- + 2H2O = (ClO4)- + 2H+ + e-
Ag+ + e- = Ag
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<span>ClO2- +Ag+ +2H2O---> ClO4^- + Ag + 2H+</span>
