Answer:
D
Explanation:
the charges need to balence out
so finding the LCM which is 12 we find we need 3x's
and 4 zs
so that makes the formula X3Z4 which is D
Hello there!
Electronegativity is what determine's an atoms ability to attract electrons shared in a chemical bond.Ionization, atomic radius, and also <span> ionic radius both would not determine this as they wouldn't have any similar bond that would attract.
</span><span>
Your correct answer would be (option c)
</span><span>A. ionization
B. atomic radius
C. electronegativity
D. ionic radius
I hope this helps you!</span>
The equation is already balanced.
Missing table!! write the elements with the first letter of the symbol with Upper Caps letters!!!
http://www.chemeddl.org/services/moodle/media/QBank/GenChem/Tables/EStandardTable.htm
<span>Ni2+ +Pb(s) → Ni(s) + Pb2+
</span>The potential of the oxidation of Pb(s) --> Pb2+(aq) is 0.126 V
The potential of the reduction go Ni2+(aq) --> Ni(s) is -0.25 V
<span>Add the two together and the potential for the reaction is -0.124 V (NO SPONTANEOUS THE SIGN IS NEGATIVE)
</span><span>au3+ + al(s) → au(s) + al3+Au3+(aq) -> Au(s) +1.5 VAl -> Al3+ +1.66VV= 3.16 (SPONTANEOUS THE SIGN OF THE PONTENTIAL IS POSITIVE)</span><span>Sr2+ + Sn(s) → Sr(s) + Sn2+
</span>
Sr2+(aq) + 2 e– <span> Sr(s) V= -2.89V
</span>Sn -> Sn2+ V= 0.14 V
V= -2.75 V (no spontaneous)
<span>Fe2+ + Cu(s) → Fe(s) + Cu2+
</span>Fe2+(aq) + 2 e–<span> </span><span> Fe(s) V= -0.44 V
</span>Cu -> C2+ V = - 0.337V
V= - 0.777V (no spontaneous)
Molarity is expressed as:
Molarity = moles / liter
Given that the cell is rod-shaped, its volume is calculated using the formula for a cylinder's volume:
V = πr²L
V = π * (0.6)² * 4.9
V = 5.54 μm³
1 Liter = 10³ mm³
1 mm = 10³ μm
1 mm³ = 10⁹ μm³
1 liter = 10¹² μm³
So the volume in liters is:
5.54 x 10⁻¹² L
Moles = molarity * liters
Moles = 0.0029 * 5.54 x 10⁻¹²
Moles = 1.61 x 10⁻¹⁴
To get the number of molecules, we multiply the moles by Avagadro's number
Number of molecules = 1.61 x 10⁻¹⁴ * 6.02 x 10²³
There are 9.69 x 10⁹ molecules in the cell