Can someone please help me on the second quick Check!!!!

There are two steps in the usual industrial preparation of acrylic acid, the immediate precursor of several useful plastics. In

qaws [65]

The question is incomplete, here is the complete question:

There are two steps in the usual industrial preparation of acrylic acid, the immediate precursor of several useful plastics. In the first step, calcium carbide and water react to form acetylene and calcium hydroxide:

$CaC_2(s)+2H_2O(g)\rightarrow C_2H_2(g)+Ca(OH)_2(s)$

In the second step, acetylene, carbon dioxide and water react to form acrylic acid:

$6C_2H_2(g)+3CO_2(g)+4H_2O(g)\rightarrow 5CH_2CHCO_2H(g)$

Write the net chemical equation for the production of acrylic acid from calcium carbide, water and carbon dioxide. Be sure your equation is balanced.

Answer: The net chemical equation is written below.

Explanation:

The intermediate balanced chemical reaction are:

(1) $CaC_2(s)+2H_2O(g)\rightarrow C_2H_2(g)+Ca(OH)_2(s)$ ( × 6 )

(2) $6C_2H_2(g)+3CO_2(g)+4H_2O(g)\rightarrow 5CH_2CHCO_2H(g)$

To omit acetylene from the net chemical reaction, we multiply Equation (1) by 6.

Equation 1: $6CaC_2(s)+12H_2O(g)\rightarrow 6C_2H_2(g)+6Ca(OH)_2(s)$

Equation 2: $6C_2H_2(g)+3CO_2(g)+4H_2O(g)\rightarrow 5CH_2CHCO_2H(g)$

Net chemical equation: $6CaC_2(s)+3CO_2(g)+16H_2O(g)\rightarrow 5CH_2CHCO_2H(g)+6Ca(OH)_2(s)$

Hence, the net chemical equation is written above.

6 0

2 years ago

The PH of a 0.1 M MCl (M is an unknown cation) was found to be 4.7. Write the net ionic equation for the hydrolysis of M and its

Serggg [28]

Answer:

6.25 X10^{-9} = Ka

$Kb= \frac{10^{-14}}{6.25 X10^{-9}}= 1.6X10^{-6}$

Explanation:

The ionic equation for the hydrolysis of the cation of the given salt will be:

$M^{+} + H_{2}O ---> MOH + H^{+}$

The expression for Ka will be:

Ka = $\frac{[H^{+}][MOH]}{[M^{+}]}$

As given that the concentration of the salt is 0.1 M and pH of solution = 4.7, we can determine the concentration of Hydrogen ions from the pH

pH = -log [H⁺]

[H⁺] = antilog(-pH) = antilog (-4.7) = 2 X 10⁻⁵ M = [MOH]

Let us calculate Ka from this,

Ka = ${2.5X10^{-5}X2.5X10^{-5}}{0.1} = 6.25 X10^{-9}$

The relation between Ka an Kb is

KaXKb =10⁻¹⁴

$Kb= \frac{10^{-14}}{6.25 X10^{-9}}= 1.6X10^{-6}$

6 0

3 years ago

NEED HELP ASAP!!!!!! describe the two different types of solids. in ur own words

Rudiy27

Answer:

crystalline and amorphous.

Explanation:

Crystalline solids are the most common type of solid, they are characterized by a regular crystalline organization of atoms that confer a long-range order, Amorphous, or non-crystalline, solids lack the long-range order

8 0

2 years ago

5. If all the particles in a material are made up of

mel-nik [20]

If all the particles in a material are made up of

several smaller particles, and every larger particle

is identical, is the material a pure substance or

not? Explain your reasoning.

A pure substance is something like a compound and element. This material made of several particles which seem to be two different particles, I believe, is a mixture. So, it is not a pure substance mixtures are made up of more than one particle while compounds (In a fixed ratio, the fusion of two or more than two atoms) and elements are made up of one molecule essentially.

4 0

2 years ago

An object that changes position relative to a reference point is

bezimeni [28]

Answer:

An object whose position changes relative to a reference location

is said to be "in motion", but only relative to the reference location.

Explanation:

5 0

2 years ago

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