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3 years ago

Which of the following would you expect to have the highest specific heat? SC.A.1.3.3

Physics

1 answer:

katovenus [111]3 years ago

7 0

B. I'm not that sure about this but i am just taking a guess

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In a game of tug of war, team one pulls to the right with a force of 500 newtons and team two pulls to the left with a force of

seraphim [82]

Answer:

Explanation:

There is no set way to do this. All you have to do is define left and right. Left will be minus and right will be the opposite --- plus.

That is completely arbitrary. It could be the other way around. It does not matter.

Left is minus so: - 600 N is the force going left.

Right plus so: + 500 N

Now just add.

Net Force = +500 - 600

Net Force = - 100 N

So the Net Force is - 100 N going to the left.

8 0

3 years ago

What do we call the center of an atom that contains the mass of the<br> with<br> ca

Delvig [45]

Answer:

Hope this helps! Please Mark Brainliest!

Explanation:

The Nucleus: The Center of an Atom. The nucleus, that dense central core of the atom, contains both protons and neutrons. Electrons are outside the nucleus in energy levels.

6 0

3 years ago

When you trace the outline of your palm how do you find its area

oksian1 [2.3K]

Answer:

Explanation:

if its squares count the squares els messure it i think

6 0

3 years ago

A wire with a length of 150 m and a radius of 0.15 mm carries a current with a uniform current density of 2.8 x 10^7A/m^2. The c

Mrac [35]

Answer:

The current is 2.0 A.

(A) is correct option.

Explanation:

Given that,

Length = 150 m

Radius = 0.15 mm

Current density $J=2.8\times10^{7}\ A/m^2$

We need to calculate the current

Using formula of current density

$J = \dfrac{I}{A}$

$I=J\timesA$

Where, J = current density

A = area

I = current

Put the value into the formula

$I=2.8\times10^{7}\times\pi\times(0.15\times10^{-3})^2$

$I=1.97=2.0\ A$

Hence, The current is 2.0 A.

7 0

3 years ago

The 9-inch-long elephant nose fish in the Congo River generates a weak electric field around its body using an organ in its tail

Alik [6]

Answer:

$1.34\cdot 10^{-16} C$

Explanation:

The strength of the electric field produced by a charge Q is given by

$E=k\frac{Q}{r^2}$

where

Q is the charge

r is the distance from the charge

k is the Coulomb's constant

In this problem, the electric field that can be detected by the fish is

$E=3.00 \mu N/C = 3.00\cdot 10^{-6}N/C$

and the fish can detect the electric field at a distance of

$r=63.5 cm = 0.635 m$

Substituting these numbers into the equation and solving for Q, we find the amount of charge needed:

$Q=\frac{Er^2}{k}=\frac{(3.00\cdot 10^{-6} N/C)(0.635 m)^2}{9\cdot 10^9 Nm^2 C^{-2}}=1.34\cdot 10^{-16} C$

4 0

3 years ago