The scale is a rest scale reads the support for is not enough net force.
Answer:
Explanation:
From the attached file diagram, the total force acting on the charged box is the downward weight and the repulsive force acting in opposite to the weight force . Hence we can write the total force as
When fixed,F=o
Hence
The value of the acceleration is 16.2m/s^2
the object has kinetic energy, because it is on the move!!
Answer:
The horizontal distance traveled by the projectile is 60 m
Explanation:
Given;
initial horizontal velocity of the projectile, Vₓ = 30 m/s
time of the motion of the projectile, t = 2 s
The horizontal distance traveled by the projectile is given by the range of the projection;
X = Vₓt
X = 30 x 2
X = 60 m
Therefore, the horizontal distance traveled by the projectile is 60 m
Therefoe
Answer:
the diver's speed is independent of the launch height.
Explanation:
For this exercise we must use Newton's second law
fr - W = m a
the friction force has the general form
fr = b v
Let's analyze this equation to find out what happens with the speed of the distant club.
When jumping, the initial speed is zero, so the friction force is zero and has an acceleration equal to the acceleration of gravity, as the speed increases the friction force increases decreasing the acceleration until it becomes zero, when it arrives at this value the velocity it has is called terminal velocity and this velocity remains fixed in relation to the trajectory.
fr = W
v = cte
The distance or time in which this equilibrium is reached is relatively fast, so the diver's speed is independent of the launch height.
