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sweet-ann [11.9K]
2 years ago
11

What was the first and largest asteroid to be identified?.

Physics
1 answer:
Lubov Fominskaja [6]2 years ago
7 0
Ceres, dwarf planet, the largest asteroid in the main asteroid belt, and the first asteroid to be discovered. Ceres was found, serendipitously, by the Italian astronomer Giuseppe Piazzi of the Palermo Observatory on January 1, 1801.
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A punter wants to kick a football so that the football has a total flight time of 4.70s and lands 56.0m away (measured along the
Sindrei [870]

Answer:

Explanation:

How long does the football need to rise?

4.70/3 = 2.35 s

What height will the football reach?

h = ½(9.81)2.35² = 27.1 m

With what speed does the punter need to kick the football?

vy = g•t = 9.81(2.35) = 23.1 m/s

vx = d/t = 56.0/4.70 = 11.9 m/s

v = √(vx²+vy²) = 26.0 m/s

At what angle (θ), with the horizontal, does the punter need to kick the football?

θ = arctan(vy/vx) = 62.7°

3 0
2 years ago
Besides gravity, what factor keeps the moon and Earth in orbit?
Gelneren [198K]

Answer:

(D) Inertia

Explanation:

Inertia words with Gravity to keep the Moon, Earth and Sun All in Orbit!

                                                      <em>-Aslina</em>

7 0
3 years ago
A grindstone of mass 12 kg and radius 0.3 m is initially rotating freely at 48 rad/sec. An axe is brought into contact with the
lesya [120]

Answer:

I = 0.54\,kg\cdot m^{2}

Explanation:

1) The moment of inertia of the grindstone is:

I = \frac{1}{2}\cdot m \cdot r^{2}

I = \frac{1}{2}\cdot (12\,kg)\cdot (0.3\,m)^{2}

I = 0.54\,kg\cdot m^{2}

4 0
3 years ago
Read 2 more answers
provides some pertinent background for this problem. A pendulum is constructed from a thin, rigid, and uniform rod with a small
gavmur [86]

Answer:

the period of the physical pendulum is 0.498 s

Explanation:

Given the data in the question;

T_{simple = 0.61 s

we know that, the relationship between T and angular frequency is;

T = 2π/ω ---------- let this be equation 1

Also, the angular frequency of physical pendulum is;

ω = √(mgL / I ) ------ let this equation 2

where m is mass of pendulum, L is distance between axis of rotation and the center of gravity of rod and I  is moment of inertia of rod.

Now, moment of inertia of thin uniform rod D is;

I = \frac{1}{3}mD²

since we were not given the length of the rod but rather the period of the simple pendulum, lets combine this three equations.

we substitute equation 2 into equation 1

we have;

T = 2π/ω OR T = 2π/√(mgL/I) OR T = 2π√(I/mgL)

so we can use I = \frac{1}{3}mD² for moment of inertia of the rod

Since center of gravity of the uniform rod lies at the center of rod

so that L =  \frac{1}{2}D.

now, substituting these equations, the period becomes;

T = 2π/√(I/mgL) OR T = 2\pi \sqrt{\frac{\frac{1}{3}mD^2 }{mg(\frac{1}{2})D } } OR T = 2π√(2D/3g )  ----- equation 3

length of rod D is still unknown, so from equation 1 and 2 ( period of pendulum ),

we have;

ω_{simple = 2π/T_{simple OR  ω_{simple = √(g/D) OR  ω_{simple = 2π√( D/g )  

so we simple solve for D/g and insert into equation 3

so we have;

T = √(2/3) × T_{simple

we substitute in value of T_{simple

T = √(2/3) × 0.61 s

T = 0.498 s

Therefore, the period of the physical pendulum is 0.498 s

 

8 0
3 years ago
What are the three types of mechanical waves?
Black_prince [1.1K]

Answer:

I'm sure its transverse, longitudinal and surface

Explanation:

sorry if I'm wrong

4 0
2 years ago
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