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Marrrta [24]
3 years ago
10

A wire with a length of 150 m and a radius of 0.15 mm carries a current with a uniform current density of 2.8 x 10^7A/m^2. The c

urrent is: A) 2.0 A B) 0.63 A C) 5.9A D) 300 A E) 26000 A
Physics
1 answer:
Mrac [35]3 years ago
7 0

Answer:

The current is 2.0 A.

(A) is correct option.

Explanation:

Given that,

Length = 150 m

Radius = 0.15 mm

Current densityJ=2.8\times10^{7}\ A/m^2

We need to calculate the current

Using formula of current density

J = \dfrac{I}{A}

I=J\timesA

Where, J = current density

A = area

I = current

Put the value into the formula

I=2.8\times10^{7}\times\pi\times(0.15\times10^{-3})^2

I=1.97=2.0\ A

Hence, The current is 2.0 A.

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4. A driver travels 135 km, east in 1.5 h, stops for 45 minutes for lunch,
stira [4]

Answer:

The driver's average velocity is 82.35 km/h.

Explanation:

Given:

The motion of the driver can be divided into 3 parts:

i. Displacement of the driver in 1.5 hours = 135 km

ii. Rest for 45 minutes.

iii. Displacement in next 2 hours = 215 km

The direction of motion remains same (east).

Now, total displacement of the driver is, D_{Total}=135+215=350 km.

Rest time is 45 minutes. Converting it to hours, we need to use the conversion factor 1\textrm{ min} = \frac{1}{60} hour.

So, 45 minutes in hours is equal to \frac{45}{60}=0.75 hours.

Now, total time taken for the complete journey is, \Delta t=1.5+\frac{45}{60}+2=1.5+0.75+2=4.25\textrm{ h}

Average velocity is given as:

v_{avg}=\frac{\textrm{Total displacement}}{Total time}=\frac{350}{4.25}=82.35\textrm{ km/h}

Therefore, the driver's average velocity is 82.35 km/h

4 0
3 years ago
Current assets minus current liabilities is known as
levacccp [35]

Answer:

Working capital is a fundamental accounting concept essential to running a business. Essentially, working capital is a company's current assets minus its current liabilities. Current assets are typically those that are highly liquid, such as cash or inventory

Explanation:

i

hope it helped...

3 0
2 years ago
A 6 kg cart starting from rest rolls down a hill and at the bottom has a speed of 10 m/s. What is the height of the hill?
Arisa [49]

Answer:

h = 5.09 m

Explanation:

Applying the Law of conservation of energy to this situation, we can write:

Kinetic\ Energy\ Gained\ by\ the\ Cart = Potential\ Energy\ Lost\ by\ the\ Cart\\\frac{1}{2}mv^2 = mgh\\\\h = \frac{v^2}{2g}

where,

h = height of the hill = ?

v = speed of cart at the end = 10 m/s

g = acceleration due to gravity = 9.81 m/s²

Therefore,

h = \frac{(10\ m/s)^2}{(2)(9.81\ m/s^2)}\\\\

<u>h = 5.09 m</u>

4 0
3 years ago
Which statements define factors that contribute to the decline of Roman Empire
USPshnik [31]
The Huns' invasion of Europe caused a mass migration driving Germanic tribes of Northern Europe to the borders of the Roman Empire which led to the Barbarian attacks on Rome. 
7 0
3 years ago
A waitperson carrying a tray with a platter on it tips the tray at an angle of 12° below the horizontal. If the gravitational fo
Nadusha1986 [10]

Answer:

The answer is 1.0 N

Explanation:

inclination of tray=12^{\circ}

gravitational Force=5 N

Now this gravitational force has two component i.e.

5\sin \theta  is parallel to the tray =1.039 N

5\cos \theta  is perpendicular to the tray =4.890 N

7 0
2 years ago
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