1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Marrrta [24]
3 years ago
10

A wire with a length of 150 m and a radius of 0.15 mm carries a current with a uniform current density of 2.8 x 10^7A/m^2. The c

urrent is: A) 2.0 A B) 0.63 A C) 5.9A D) 300 A E) 26000 A
Physics
1 answer:
Mrac [35]3 years ago
7 0

Answer:

The current is 2.0 A.

(A) is correct option.

Explanation:

Given that,

Length = 150 m

Radius = 0.15 mm

Current densityJ=2.8\times10^{7}\ A/m^2

We need to calculate the current

Using formula of current density

J = \dfrac{I}{A}

I=J\timesA

Where, J = current density

A = area

I = current

Put the value into the formula

I=2.8\times10^{7}\times\pi\times(0.15\times10^{-3})^2

I=1.97=2.0\ A

Hence, The current is 2.0 A.

You might be interested in
What do you think happened to the energy you transferred to the notebook when you pushed it?
xeze [42]

Answer:

It got transferred to kinetic energy

Explanation:

8 0
3 years ago
Read 2 more answers
Select the correct answer from each drop-down menu.
-Dominant- [34]

Answer:

And the force of ( Attraction or repulsion) between the poles A and D ( maximum or minimum)

4 0
3 years ago
Read 2 more answers
Question 6
Effectus [21]

Answer:

4.9 x 10-23 N

Explanation:

I took the test

3 0
3 years ago
The eyepiece of a light microscope has a magnification level of 10x. If you were looking at a paramecium under the lowest-power
tester [92]

Answer:

The total magnification will be 40x.

Explanation:

As we know if the magnification of the eyepiece of a microscope be m_{e} and that of the objective be m_{o}, then the total magnification is given by

m = m_{e} \times m_{o}

Given, m_{e} = 10x and m_{o}  = 4x

Therefore total magnification is m = 10 \times 4 = 40x

4 0
3 years ago
Does time stop in a black hole
lbvjy [14]

Answer:

In standard GR, nothing exists at the center of a black hole. The center of a black hole is a singularity, and because GR fails at that point it is simply removed from the manifold. That means that the singularity is not part of spacetime.

To answer your question more realistically, we believe that GR is an approximate theory that fails well before you reach the center. Unfortunately, we have no good alternative theory with which to answer the question in the region where GR fails. We simply don’t have any data from that regime and it is very hard to formulate a good theory without data. So there very well could be time at the center, but we simply don’t have a good way to even guess.

4 0
3 years ago
Read 2 more answers
Other questions:
  • A small 21 kilogram canoe is floating downriver at a speed of 1 m/s. What is the canoe's kinetic energy?
    12·1 answer
  • How do magnets act when they are near eachother ?
    15·1 answer
  • 1. Which of the following does Kepler's Second Law support?
    5·1 answer
  • Which best supports the idea that the surface of the moon has changed very little?
    5·2 answers
  • Change a speed of 72.4 miles per hour to its equivalent in meters per second.
    9·1 answer
  • The truck is described as travelling at 30mph to the west. The quantity described here is a(n)
    8·1 answer
  • A ball with a mass of 3 kg moving at 5 m/s collides with a 9 kg ball at rest. After the collision, the impacting (3 kg) ball bou
    8·1 answer
  • A cat rolls up a hill. It’s initial Velocity is 10 m/s.n It’s final velocity is 0 m/s. The time was five seconds. Calculate Acce
    5·1 answer
  • 9) What will happen to the period of a pendulum if we change the rope of a pendulum with another which is four times with the in
    7·1 answer
  • Two rockets are being tested. Both rockets have the same mass. One rocket accelerates at a higher rate than another rocket. What
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!