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Assoli18 [71]
3 years ago
7

A 0.9 µF capacitor is charged to a potential difference of 10.0 V. The wires connecting the capacitor to the battery are then di

sconnected from the battery and connected across a second, initially uncharged, capacitor. The potential difference across the 0.9 µF capacitor then drops to 2 V. What is the capacitance of the second capacitor?
Physics
1 answer:
jeyben [28]3 years ago
7 0

Answer:

3.6μF

Explanation:

The charge on the capacitor is defined by the formula

q = CV

because the charge will be conserved

q₁ = C₁V₂

q₂ = C₂V₂ where C₂ V₂ represent the charge on the newly connected capacitor  and the voltage drop across the two capacitor will be the same

q = q₁ + q₂ = C₁V₂ + C₂V₂

CV = CV₂ + C₂V₂

CV - CV₂ = C₂V₂

C ( V - V₂) = C₂V₂

C ( V/ V₂ - V₂ /V₂) = C₂

C₂ = 0.9 ( 10 /2) - 1) = 0.9( 5 - 1) = 3.6μF

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guapka [62]

Answer:

They two waves has the same amplitude and frequency but different wavelengths.

Explanation: comparing the wave equation above with the general wave equation

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4 0
3 years ago
Light of wavelength 597 nm falls on a double slit, and the first bright fringe of the interference pattern is seen at an angle o
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Answer:

2.2 µm

Explanation:

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Given wavelength = 597 nm

Angle, \theta  = 15.8°

First bright fringe means , m = 1

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d\times sin\ 15.8^0=1\times \597\ nm

d\times 0.2723=1\times \597\ nm

d=2192.43481\ nm

Also,

1 nm = 10⁻⁹ m

1 µm = 10⁻⁶ m

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1 nm = 10⁻³ nm

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8 0
3 years ago
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ser-zykov [4K]

Answer:

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garri49 [273]

Answer:

The depth is 5.15 m.

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The total pressure at the bottom of the pool =  (P + ρ g h) a

The bottom and the top force is same

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P a +ρ g h a =  P A

ρ g h a =  P A - P a

h=\dfrac{P ( A-a)}{\rho g a}

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h=\dfrac{P ( 1.5- 1)}{\rho g}

h=\dfrac{101235 ( 1.5- 1)}{1000\times 9.81}\ m

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7 0
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An old theory about the creation of the universe has been replaced by a new theory. Which of these statements is correct about t
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