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Margarita [4]
4 years ago
13

Radio waves, visible light, and x-rays are exempted of electromagnetic waves that always differ from each other in?

Physics
1 answer:
leva [86]4 years ago
6 0
I think wavelength is the correct answer. Correct me if Im wrong. Hope this helps!
You might be interested in
The term fetus completes which of the following lists to show the correct order of development?
netineya [11]
The answer is C............
8 0
3 years ago
If one motor has three times as much power as another, then the smaller power motor: A. can do the same work in the same time. B
Dvinal [7]

Answer:B

Explanation:

Given

First motor has three times as much as power as another

Let the power of smaller motor be P

Therefore bigger motor has power 3 P

and we know that energy E=power\times time

Larger motor E=3P\times t=3Pt

Smaller motor E=P\times 3t=3Pt

Therefore smaller motor will do same work if it takes three times the time taken by Larger motor

8 0
4 years ago
A box with mass m = 8 kg is pushed x = 10 m across a level floor by a constant applied force F P = 16.27 N. The coefficient of k
vitfil [10]

Answer:

Final speed of the box after it has moved to x = 10 is given as

v = 3.35 m/s

Explanation:

As we know by work energy theorem that work done by all the forces is equal to the change in its kinetic energy

Here work done by external force + work done by friction = change in kinetic energy of the box

so we have

W_{ex} + W_{fric} = \frac{1}{2}mv^2

F x - \mu mg x = \frac{1]{2}mv^2

16.27 (10) - (0.15)(8)(9.8) (10) = \frac{1}{2}(8) v^2

162.7 - 117.6 = 4 v^2

v = 3.35 m/s

4 0
3 years ago
A 1500-kg car traveling east with a speed of 25.0 m/s collides at an intersection with a 2500-kg van traveling north at a speed
IgorC [24]

Answer:

The direction and magnitude of velocity is 38.65° and 12.005 m/s

Explanation:

Given that,

Mass of car = 1500 kg

Speed of car = 25.0 m/s

Mass of van = 2500 kg

Speed of van =20.0 m/s

We need to calculate the velocity

Using conservation of energy

m_{c}u_{i}+m_{v}u_{i}=(m_{c}+m_{v})v_{f}

1500(25i+0j)+2500(0+20j)=4000(v_{f})

v_{f}=\dfrac{1500\times25}{4000}i+\dfrac{1500\times20}{4000}j

v_{f}=9.375 i+7.5 j

The magnitude of velocity

|v_{f}|=\sqrt{(9.375)^2+(7.5)^2}

|v_{f}|=12.005\ m/s

We need to calculate the direction

\tan\theta=\dfrac{coefficient\ of\ j}{coefficient\ of\ i}

\tan\theta=\dfrac{7.5}{9.375}

\theta=\tan^{-1}0.8

\theta=38.65^{\circ}

Hence, The direction and magnitude of velocity is 38.65° and 12.005 m/s.

3 0
4 years ago
Help! Will Mark Brainliest!
boyakko [2]

Answer:

D 5m/s

Explanation:

6 0
3 years ago
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