Momentum is conserved when carts are collided on a slanting plane.
To find the answer, we need to know about the conversation of momentum.
<h3>What's the conversation of momentum?</h3>
- Conservation of linear momentum says the total momentum before the collision and after the collision remains the same.
- Mathematically, m1u1+m2u2 = m1v1+m2v2
<h3>How is the momentum conserved when collision occurs on a slanting plane?</h3>
- On a slanting plane, the velocity has two components,
- horizontal component
- horizontal component Vertical component
- So, its momentum has also similar two components.
- The momentum is conserved along horizontal direction and vertical direction separately.
Thus, we can conclude that the momentum is conserved when carts are collided on a slanting plane.
Learn more about the conversation of momentum here:
brainly.com/question/7538238
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The tree might get swept away by the current and it will disappear when it catches on something
Answer:
Kinetic energy of bigger rock will be more than that of smaller one.
Explanation:
Kinetic energy of the rock is given by,
Kinetic energy = 
As velocity of both the rocks are same. Thus, kinetic energy is directly proportional to the mass of the rock
Kinetic energy ∝ mass
So, For greater mass kinetic energy will be greater and for smaller mass kinetic energy will be smaller.
Hence, Kinetic energy of bigger rock will be more than that of smaller one.
Answer: option d: The nucleus of Atom Q is more stable than the nucleus of Atom P.
Explanation:
Atom P is radioactive and disintegrates, it emits beta particles (high speed electrons or positrons) because it is not stable. On disintegration, it forms a stable Atom Q which is non-radioactive and thus it does not disintegrates further.
Thus, the correct option is only d. The nucleus of Atom Q is more stable than the nucleus of Atom P.
At t=0, the particle was at its equilibrium position. The time period is 32 seconds, so in 8 seconds, it will reach the extreme location once, and hence, in 8 seconds, it will cover a distance equivalent to its amplitude.
