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elena-s [515]
1 year ago
11

S Assume you have a battery of emf E and three identical lightbulbs, each having constant resistance R. What is the total power

delivered by the battery if the lightbulbs are connected (c) For which connection will the lightbulbs shine the brightest?
Physics
1 answer:
slega [8]1 year ago
8 0

The total power delivered by the battery if the lightbulbs are connected is 9V^2/R

<h3>Power of a battery</h3>

The formula for calculating the power of a battery is expressed according to the equation;

Power = v^2/RT

where

R is the total resistance

v is the voltage or emf

If there are 3 identical lightbulbs, each having constant resistance R, then;

1/RT = 1/R + 1/R + 1/R

1/RT = 3/R

RT = R/3

The voltage drop across each   lightbulbs will be the same for parallel connection, hence;

Power = 3V^2/(R/3)

Power = 9V^2/R

Hence the total power delivered by the battery if the lightbulbs are connected is 9V^2/R

Learn more on power here: brainly.com/question/24858512

#SPJ4

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Answer:

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Potential\ Energy=3*\frac{kq^2}{r}

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