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Elodia [21]
3 years ago
15

Which factors would increase heating of Earth, and which factors would decrease it

Physics
2 answers:
yawa3891 [41]3 years ago
7 0
I don’t know really really I don’t know
loris [4]3 years ago
4 0

Answer:

So as sunlight continued to enter the box and the walls continued to warm, heat built up inside and increased the temperature.

You might be interested in
This group of elements is in group 2?
asambeis [7]

Answer:

If you meant the Periodic Table it's the alkaline-earth metal

beryllium (Be)

magnesium (Mg)

calcium (Ca)

strontium (Sr)

barium (Ba)

radium (Ra)

Explanation:

5 0
2 years ago
EM waves consist of changing electric and magnetic fields moving perpendicular with respect to each other. What kind of wave is
Serhud [2]

Answer:

Transverse

Explanation:

Electromagnetic waves don't depend on the medium they travel through like a mechanical wave does, so they aren't mechanical. They don't oscillate (move back in forth) in the direction they travel either, ruling out compressional and longitudinal waves.

That leaves tranverse waves, the ones we're most used to, since they look very "wavelike," with smooth peaks and valleys. Electromagnic waves behave like these, oscillating in a plane perpendicular to the direction they're traveling in.

5 0
3 years ago
A machine is rolling a metal cylinder under pressure. The radius of the cylinder is decreasing at a constant rate of 0.05 inches
Luden [163]
Yes, the volume of the cylinder will remain constant. As the radius decreases, the height will increase to make sure that the volume is kept the same.
We have been given a value of dr/dt and are required to find dh/dt
Because the volume is constant, we can plug it into the formula for the volume of the cylinder and rearrange it to make h the subject:
128 = πr²h
h = 128/πr²
Now we differentiate both sides:
dh/dr = -256/πr³
Applying the chain rule:
dh/dt = dh/dr x dr/dt
dh/dt = (-256/πr³) x -0.05
dh/dt = 64/5πr³; substituting the value of r
dh/dt = 64/5π(1.5)³
dh/dt = 1.21 in/sec
4 0
3 years ago
How long tg does it take for the balls to reach the ground? use 10 m/s2 for the magnitude of the acceleration due to gravity.
erik [133]

Answer:

1.0s

Explanation:

distance = 1/2 × acceleration × time2 + intial speed × time

5 0
3 years ago
An astronaut finds herself in a predicament in which she has become untethered from her shuttle. She figures that she could get
Blizzard [7]

In order to solve the problem, it is necessary to apply the concepts related to the conservation of momentum, especially when there is an impact or the throwing of an object.

The equation that defines the linear moment is given by

mV_i = (m-m_O)V_f - m_OV_O

where,

m=Total mass

m_O = Mass of Object

V_i = Velocity before throwing

V_f = Final Velocity

V_O = Velocity of Object

Our values are:

m_1=5.3kgm_2=7.9kg\\m_3=10.5kg\\m_A=75kg\\m_{Total}=m=98.7Kg

Solving to find the final speed, after throwing the object we have

V_f=\frac{mV_0+m_TV_O}{m-m_O}

We have three objects. For each object a launch is made so the final mass (denominator) will begin to be subtracted successively. In addition, during each new launch the initial speed will be given for each object thrown again.

That way during each section the equations should be modified depending on the previous one, let's start:

A) 5.3Kg\rightarrow 15m/s

V_{f1}=\frac{mV_0+m_TV_O}{m-m_O}

V_{f1}=\frac{(98.7)*0+5.3*15}{98.7-5.3}

V_{f1}=0.8511m/s

B) 7.9Kg\rightarrow 11.2m/s

V_{f2}=\frac{mV_{f1}+m_TV_O}{m-m_O}

V_{f2}=\frac{(98.7)(0.8511)+(7.9)(11.2)}{98.7-5.3-7.9}

V_{f2} = 2.0173m/s

C) 10.5Kg\rightarrow 7m/s

V_{f3}=\frac{mV_{f2}+m_TV_O}{m-m_O}

V_{f3}=\frac{(98.7)(2.0173)+(10.5)(7)}{98.7-5.3-7.9-10.5}

V_{f3} = 3.63478m/s

Therefore the final velocity of astronaut is 3.63m/s

7 0
3 years ago
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