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Elodia [21]
3 years ago
15

Which factors would increase heating of Earth, and which factors would decrease it

Physics
2 answers:
yawa3891 [41]3 years ago
7 0
I don’t know really really I don’t know
loris [4]3 years ago
4 0

Answer:

So as sunlight continued to enter the box and the walls continued to warm, heat built up inside and increased the temperature.

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Interest groups representing businesses and investors are often among the most successful lobbying groups in foreign policy. Why
alisha [4.7K]

The members of these groups make up the majority of voters in many districts thus this  be considered a problem.

<u>Option: D</u>

<u>Explanation:</u>

Interest groups play a key role in US politics. Such organizations are made up of wealthy and powerful members who often seek to impose some form of leverage in politicians to promote their goals and agendas. Across the years via many campaigns, they have understood how to speak and manipulate elected leaders and apply leverage to get the kind of legislation that is in their favor. Here the majority of voters in several districts are standing due to group members, as we recognize the interest group belongs to a body in which it uses different methods of lobbying to influence others.

7 0
4 years ago
Which term below describes a measurement of how hard an object pushes against a surface?
Scilla [17]

I hope the answer is D. Pressure

8 0
3 years ago
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A terain tarvels 120 I in 2 hours and 30 mins .what is its average speed
Zarrin [17]

Answer:

It's speed is 48 km/hr.

Explanation:

6 0
3 years ago
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____ is a pesticide that influenced society by increasing crop yield, but it also caused human and animal sickness.
Ilya [14]

I think your answer would be DDT, but don't hold me to it

5 0
4 years ago
A supersonic nozzle is also a convergent–divergent duct, which is fed by a large reservoir at the inlet to the nozzle. In the re
Lady_Fox [76]

Answer:

155.38424 K

2.2721 kg/m³

Explanation:

P_1 = Pressure at reservoir = 10 atm

T_1 = Temperature at reservoir = 300 K

P_2 = Pressure at exit = 1 atm

T_2 = Temperature at exit

R_s = Mass-specific gas constant = 287 J/kgK

\gamma = Specific heat ratio = 1.4 for air

For isentropic flow

\frac{T_2}{T_1}=\frac{P_2}{P_1}^{\frac{\gamma-1}{\gamma}}\\\Rightarrow T_2=T_1\times \frac{P_2}{P_1}^{\frac{\gamma-1}{\gamma}}\\\Rightarrow T_2=00\times \left(\frac{1}{10}\right)^{\frac{1.4-1}{1.4}}\\\Rightarrow T_2=155.38424\ K

The temperature of the flow at the exit is 155.38424 K

From the ideal equation density is given by

\rho_2=\frac{P_2}{R_sT_2}\\\Rightarrow \rho=\frac{1\times 101325}{287\times 155.38424}\\\Rightarrow \rho=2.2721\ kg/m^3

The density of the flow at the exit is 2.2721 kg/m³

4 0
3 years ago
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