What are the compounds used in nanotechnology

1 answer:

7 0

The remaining 3 % are nanomaterials made from e.g. aluminium oxide, barium titanate, titanium dioxide, cerium oxide and zinc oxide. Carbon nanotubes, graphene and fullerenes have annual production amounts in the hundred tonnes range. Nanosilver is estimated to be produced in about 20 tonnes per year.

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Name the phase change in each of these events: (a) A diamond film forms on a surface from gaseous carbon atoms in a vacuum.

labwork [276]

The phase shift in the events is called deposition.

In a vacuum, carbon atoms in gas form a diamond coating on a surface. The conversion of gas phase to solid phase is a part of the described process. As a result, this procedure is known as deposition.

A deposition is a process by which a solid substance is formed from a gaseous one. Bypassing the transitional liquid state, a gaseous substance is deposited in its place (often as crystals). Deposition happens, for instance, when airborne water vapor quickly freezes into ice, as when frost develops.

<h3>How does deposition occur?</h3>

Whether the eroding agent is gravity, ice, water, waves, or wind, deposition happens when it runs out of energy and can no longer support the burden of the degraded material. Gravity or, in the case of wind, the Sun, provides the energy that the erosion agents can use.

Learn more about deposition: brainly.com/question/12081679

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4 0

1 year ago

If 5 mol of oxygen gas effuses through an opening in 10 seconds, how long will it take for the same amount of hydrogen gas to ef

andrezito [222]

Answer:

Explanation:

Recall the law of effusion:

$\displaystyle \frac{r_1}{r_2} = \sqrt{ \frac{\mathcal{M}_2}{\mathcal{M}_1} }$

Because 5 mol of oxygen was effused in 10 seconds, the rate is 0.5 mol/s.

Let the rate of oxygen be <em>r</em>₁ and the rate of hydrogen be <em>r</em>₂.

The molecular weight of oxygen gas is 32.00 g/mol and the molecular weight of hydrogen gas is 2.02 g/mol.

Substitute and solve for <em>r</em>₂:

$\displaystyle \begin{aligned} \frac{(0.5\text{ mol/s})}{r_2} & = \sqrt{\frac{(2.02\text{ g/mol})}{(32.00\text{ g/mol})}} \\ \\ r_2 & = \frac{0.5\text{ mol/s}}{\sqrt{\dfrac{(2.02\text{ g/mol})}{(32.00\text{ g/mol})}}} \\ \\ & = 2.0\text{ mol/s}\end{aligned}$

Because there are 5 moles of hydrogen gas:

$\displaystyle 5.0\text{ mol} \cdot \frac{1\text{ s}}{2.0\text{ mol}} = 2.5\text{ s}$

In conclusion, it will take about 2.5 seconds for the hydrogen gas to effuse.

Check: Because hydrogen gas is lighter than oxygen gas, we expect that hydrogen gas will effuse quicker than oxygen gas.

6 0

2 years ago

What is the empirical formula for c12h24o6? what is the empirical formula for c12h24o6? ch2o cho c2h5o c2h4o cho2?

stira [4]

Empirical formula: The formula consist of proportions of the elements which is present in the compound or the simplest whole number ratios of atoms.

Now, molecular formula is equal to the product of n (ratio) and empirical formula.

Molecular formula = $n\times empirical formula$ (1)

molecular formula = $C_{12}H_{24}O_{6}$ (given)

Since, 6 is the smallest subscript in above molecular formula to get the simpler whole number of atoms. Therefore, divide all the subscripts i.e. number of carbon atoms (12), number of hydrogen atoms (24) and number of oxygen atoms (6) by 6.

empirical formula becomes $C_{2}H_{4}O$