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schepotkina [342]
3 years ago
13

What are the compounds used in nanotechnology

Chemistry
1 answer:
Doss [256]3 years ago
7 0
The remaining 3 % are nanomaterials made from e.g. aluminium oxide, barium titanate, titanium dioxide, cerium oxide and zinc oxide. Carbon nanotubes, graphene and fullerenes have annual production amounts in the hundred tonnes range. Nanosilver is estimated to be produced in about 20 tonnes per year.




I looked this up but hope it helps
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Sorry it’s for science
garik1379 [7]

Answer:

A

Explanation:

Density/Formula

\rho ={\frac {m}{V}}

\rho = density

m = mass

V = volume

5 0
3 years ago
HELP DUE MONDAY!!<br> Don’t understand
Katyanochek1 [597]

Answer:

Concept: Chemical Analysis

  1. You need to start by graphing the data and then analyzing it.
  2. We can see that the horse has a distance in meters of 980 at the end of the 10 seconds hence it is the fastest.
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5 0
3 years ago
A topographical map of a section of Charleston, SC is shown. What feature is located at the dot marked with an X? A) the center
Effectus [21]
It seems that you have missed the given image to answer this question. But anyway, I found it and got the answer. Based on the  topographical map of a section of Charleston, SC, the feature that is <span>located at the dot marked with an X is the high point of a hill. The answer would be option D.</span>
6 0
3 years ago
Observations of the solar system support the nebular theory because
motikmotik

Answer:

Because all the planets orbit the sun in the same direction, along a circular flattened disk.

Explanation:

You're welcome bro, sorry for the late answer

6 0
4 years ago
Read 2 more answers
Each step in the following process has a yield of 90.0 %. CH 4 + 4 Cl 2 ⟶ CCl 4 + 4 HCl CCl 4 + 2 HF ⟶ CCl 2 F 2 + 2 HCl The CCl
Rainbow [258]

Answer:

4.86 moles of HCl

Explanation:

1. First write the balanced chemical equations involved in the process:

CH_{4}+_4Cl_{2}=CCl_{4}+_4HCl

CCl_{4}+_2HF=CCl_{2}+F_{2}+_2HCl

2. Calculate what amount of CCl_{4} is formed in the first reaction.

3.00molesCH_{4}*\frac{1molCCl_{4}}{1molCH_{4}}=3.00molesCCl_{4}

As the yield of each reaction is 90.0%, the amount of CCl_{4} produced is the following:

3.00molesCCl_{4}*0.90=2.7molesCCl_{4}

3. Calculate the amount of HCl produced.

2.7molesCCl_{4}*\frac{2molHCl}{1molCCl_{4}}=5.4molesHCl

The total amount of HCl produced with a 90.0% yield is:

5.4molesHCl*0.90=4.86molesHCl

4 0
3 years ago
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