Third choice because the others make no sense
Answer:
The fundamental principle involves the formation of equilibrium and separation into distillate and bottoms governed by the equilibrium composition curve , number of stages and the purity with which the distillate is required.
Explanation:
Distillation is a type of the separation process by physical means of a mixture on basis of its difference in boiling point or vapor pressure .
Where we can just heat the mixture and separate out the components i.e the component with lower boiling point will form vapor easily and can be later condensed whereas the component with higher boiling point will remain as residue.
In case of a distillation column the same principle is applied at different stages to separate multiple components .The stages are known as trays or plates . In general , there is a certain liquid on each of the plate, and the arrangements are made for the ascending vapors to pass through the liquid and make contact with it . The fundamental principle involves the formation of equilibrium and separation into distillate and bottoms governed by the equilibrium composition curve , number of stages and the purity with which the distillate is required.
Answer:
Beryllium has an electronic configuration of 1s2 2s2 in its natural state. When in an ion state of Be2+ it loses the electrons in a 2s shell and has a configuration of 1s2. This means that Be2+ has 2 electrons.
Answer:
The final temperature of the solution is 44.8 °C
Explanation:
assuming no heat loss to the surroundings, all the heat of solution (due to the dissolving process) is absorbed by the same solution and therefore:
Q dis + Q sol = 0
Using tables , can be found that the heat of solution of CaCl2 at 25°C (≈24.7 °C) is q dis= -83.3 KJ/mol . And the molecular weight is
M = 1*40 g/mol + 2* 35.45 g/mol = 110.9 g/mol
Q dis = q dis * n = q dis * m/M = -83.3 KJ/mol * 13.1 g/110.9 gr/mol = -9.84 KJ
Qdis= -9.84 KJ
Also Qsol = ms * Cs * (T - Ti)
therefore
ms * Cs * (T - Ti) + Qdis = 0
T= Ti - Qdis * (ms * Cs )^-1 =24.7 °C - (-9.84 KJ/mol)/[(104 g + 13.1 g)* 4.18 J/g°C] *1000 J/KJ
T= 44.8 °C
Answer:
Anhydrous calcium chloride dissolves and becomes liquid
Anhydrous copper (ii) sulphate will produce crystal particles
Explanation:
Anhydrous calcium chloride is deliquescent and hence when it is exposed to air, it absorbs water from air. After absorbing water, it dissolves and after some time a pool of clear liquid appears.
Anhydrous copper (ii) sulphate will form crystal structures and the following reaction will takes place
CuSO4 + 5 H20 --> CuSO4.5H2O
