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Nonamiya [84]
3 years ago
10

Or n: -6n + 9 = 1 - 5n your answer. I need help please

Mathematics
1 answer:
12345 [234]3 years ago
6 0

Answer:

Please

Step-by-step explanation:

Subistitute the nś

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Find the Jacobian ∂(x, y, z) ∂(u, v, w) for the indicated change of variables. If x = f(u, v, w), y = g(u, v, w), and z = h(u, v
jeyben [28]

Answer:

The Jacobian ∂(x, y, z) ∂(u, v, w) for the indicated change of variables

= -3072uv

Step-by-step explanation:

<u>Step :-(i)</u>

Given  x = 1 6 (u + v)  …(i)

  Differentiating equation (i) partially with respective to 'u'

               \frac{∂x}{∂u} = 16(1)+16(0)=16

  Differentiating equation (i) partially with respective to 'v'

              \frac{∂x}{∂v} = 16(0)+16(1)=16

  Differentiating equation (i)  partially with respective to 'w'

               \frac{∂x}{∂w} = 0

Given  y = 1 6 (u − v) …(ii)

  Differentiating equation (ii) partially with respective to 'u'

               \frac{∂y}{∂u} = 16(1) - 16(0)=16

 Differentiating equation (ii) partially with respective to 'v'

               \frac{∂y}{∂v} = 16(0) - 16(1)= - 16

Differentiating equation (ii)  partially with respective to 'w'

               \frac{∂y}{∂w} = 0

Given   z = 6uvw   ..(iii)

Differentiating equation (iii) partially with respective to 'u'

               \frac{∂z}{∂u} = 6vw

Differentiating equation (iii) partially with respective to 'v'

               \frac{∂z}{∂v} =6 u (1)w=6uw

Differentiating equation (iii) partially with respective to 'w'

               \frac{∂z}{∂w} =6 uv(1)=6uv

<u>Step :-(ii)</u>

The Jacobian ∂(x, y, z)/ ∂(u, v, w) =

                                                         \left|\begin{array}{ccc}16&16&0\\16&-16&0\\6vw&6uw&6uv\end{array}\right|

   Determinant       16(-16×6uv-0)-16(16×6uv)+0(0) = - 1536uv-1536uv

                                                                                 = -3072uv

<u>Final answer</u>:-

The Jacobian ∂(x, y, z)/ ∂(u, v, w) = -3072uv

 

               

     

6 0
3 years ago
chase and sara went to the candy store. chase bought 5 pieces of fudge and 3 pieces of gum for 5.70. sara bought 2 pieces of fud
Vilka [71]
Let, the cost of 1 piece of fudge = x
Cost of a gum = y

System of equations: 5x + 3y = 5.70
2x + 10y = 3.60

Multiply 1st equation by 2, and second by 5, 
New equations: 10x + 6y = 11.40
10x + 50y = 18

Now, subtract 1st from 2nd, 
44y = 6.60
y = 6.60 / 44
y = 0.15

Substitute it in second equation, 
2x + 10(0.15) = 3.60
2x = 3.60 - 1.5
x = 2.10 / 2
x = 1.05

In short, Cost of a Fudge = $1.05 & Cost of a gum = $0.15

Hope this helps!
6 0
3 years ago
Which should be the first step in solving the equation 1.2w-3.8=12.4
zaharov [31]

Answer:

+3.8 to each side

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Which ratio forms a proportion with 7/4?<br><br>A. 49 <br>B.1512 <br>C. 25 <br>D. 36
Liono4ka [1.6K]
D


The andwer is d

D is yeh answer
4 0
3 years ago
A fair coin is flipped four times. What is the probability of getting heads at least once?
Llana [10]
The probability is 15.63%. Solution:
 (1 + 4)! over (1! + 4! + 2 raise to 5)
=5/32
=.1563
=15.63%
6 0
3 years ago
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