Answer:
can be written in power notation as 
Step-by-step explanation:
The given expression

Writing a\times (-a)\times 13\times a\times (-a)\times 13 in power notation:
Let

= ![[13\times13][(a\times (-a)\times a\times (-a)]](https://tex.z-dn.net/?f=%5B13%5Ctimes13%5D%5B%28a%5Ctimes%20%28-a%29%5Ctimes%20a%5Ctimes%20%28-a%29%5D)
As
,
,
So,
![=[13^{2}][a^2\times (-a)^2]](https://tex.z-dn.net/?f=%3D%5B13%5E%7B2%7D%5D%5Ba%5E2%5Ctimes%20%28-a%29%5E2%5D)
As

So,
![=[13^{2}][a^2\times a^2]](https://tex.z-dn.net/?f=%3D%5B13%5E%7B2%7D%5D%5Ba%5E2%5Ctimes%20a%5E2%5D)
As ∵
![=[13^{2}][a^{2+2}]](https://tex.z-dn.net/?f=%3D%5B13%5E%7B2%7D%5D%5Ba%5E%7B2%2B2%7D%5D)
As ∵


Therefore,
can be written in power notation as 
<em>Keywords: power notation</em>
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Answer:
16,000,000
Step-by-step explanation:
to start off your going to need to use PEMDAS (parenthesis exponents multiplication division addition subtraction)
so we are going to start IN the parenthesis the next step is doing the exponents so its going to look like this 1,000,000
rewrite the problem: 4(4×1,000,000)
use the next step in PEMDAS multiplication rewrite the problem:
4(4,000,000)
multiply: 16,000,000
For this equation, you want to do it in fractions/ratios to properly solve it. You would have his average misses out of every field goal and his real missed attempts over total. It would look like this

=

You want to solve for x since x is the total amount of field goals that he attempted. You can do this by doing cross multiplication:
(2)(x) = (8)(11)
From here you can get:
2x = 88
Divide each side by 2 to isolate x and you get:
x= 44
So he made a total of 44 field goals.