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sveta [45]
3 years ago
11

What is squad root of 128?

Mathematics
2 answers:
Vikentia [17]3 years ago
5 0
The square root of 128 is <span>11.313708499</span>
DanielleElmas [232]3 years ago
4 0
The square root of something is a number that you can multiply by it self and equals the number you are looking for. for example the square root of 144 is 12. you can multiply 12 by 12 and get 144. now that you know what a square root is you can probably figure out how to find the square root of 128 if not just tell me and i will help you 


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the zeros of a parabola are -4 and 2, and (6, 10) is a point on the graph. which equation can be solved to determine the value o
natka813 [3]
Sure this question comes with a set of answer choices.

Anyhow, I can help you by determining one equation that can be solved to determine the value of a in the equation.

Since, the two zeros are - 4 and 2, you know that the equation can be factored as the product of (x + 4) and ( x - 2) times a constant.  This is, the equation has the form:

y = a(x + 4)(x - 2)

Now, since the point (6,10) belongs to the parabola, you can replace those coordintates to get:

10 = a (6 + 4) (6 - 2)

Therefore, any of these equivalent equations can be solved to determine the value of a:

10 = a 6 + 40) (6 -2)

10 = a (10)(4)

10 = 40a
7 0
3 years ago
Read 2 more answers
Find the value of the variable in the figure provided <br><br><br> PLEASE HELP ASAP
Harlamova29_29 [7]

Answer:

x=17

Step-by-step explanation:

(5x-58)=(2x-7)  ->(because of cosine-rule)

3x=51

x=17

6 0
3 years ago
According to the US Bureau of labor statistics, 7% of US female workers between 16 and 24 years old are paid at the minimum wage
vladimir1956 [14]

Answer:

The Null Hypothesis is  H_o:k_o = 0.07

The alternative hypothesis is  H_a :k_o \ne 0.07

Decision rule

    If the test staistics is  greater than the critical value of significance level then H_o is accepted else H_o  is rejected

With the above in mind

       The critical value of the significance level which is obtained from the table is

     t_{0.05} = 1.645

Now since the critical value of significance level is greater than the test  staistics then the null hypothesis will be rejected

Conclusion

The information is not enough to back the claim that state differs from the nation

Step-by-step explanation:

From the question we are told that

The percentage of US female workers paid at the minimum wage or less is  k_o = 7% = 0.07

  The sample size is  n =  500

    The number paid minimum wage or less is  x = 42

    The significance level is \alpha  =5%  = 0.05

Now the probability of getting a US female workers paid at the minimum wage or less is mathematically represented as

         \= k = \frac{x}{n}

substituting value

        \= k = \frac{42}{500}

        \= k = 0.084

The Null Hypothesis is  H_o:k_o = 0.07

The alternative hypothesis is  H_a :k_o \ne 0.07

Generally the test statistics is mathematically evaluated as

        z =  \frac{\=  k  - k_o}{\sqrt{\frac{k_o(1-k_o)}{n} } }

substituting value

      z =  \frac{0.084  - 0.07}{\sqrt{\frac{0.07 (1-0.07)}{500} } }

     z =  1.23

Now the Decision rule is stated as  

        If the test staistics is  greater than the critical value of significance level then H_o is accepted else H_o  is rejected

With the above in mind

       The critical value of the significance level which is obtained from the table is

     t_{0.05} = 1.645

Now since the critical value of significance level is greater than the test  staistics then the null hypothesis will be rejected

   So the conclusion will be

   The information is not enough to back the claim that state differs from the nation

 

4 0
4 years ago
Please help me !!! need help will mark brainly
Ronch [10]

Answer:

1. is 3 2/3

2. is 3 1/4

3. is 2 1/4

Hope this helped! :)

4 0
4 years ago
Help me in this algebra1 problem
sergeinik [125]
X=kevin
<span>y=steve </span>
<span>x+y=26 </span>

<span>x=4+y </span>

(4+y)+y=26
<span>-4 -4 </span>


<span>y+y=22 </span>

2y=22
<span>/2 /2 
</span>
<span>y=11 </span>

<span>steve ran 11 miles</span>
8 0
4 years ago
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