For the answer to the question above,
we can get the number of fringes by dividing (delta t) by the period of the light (Which is λ/c).
fringe = (delta t) / (λ/c)
We can find (delta t) with the equation:
delta t = [v^2(L1+L2)]/c^3
Derivation of this formula can be found in your physics text book. From here we find (delta t):
600,000^2 x (11+11) / [(3x10^8)^3] = 2.93x10^-13
2.93x10^-13/ (589x10^-9 / 3x10^8) = 149 fringes
This answer is correct but may seem large. That is because of your point of reference with the ether which is usually at rest with respect to the sun, making v = 3km/s.
The answers to the problem are as follows:
MA= 5
IMA= input distance/ output distance, 5
<span>AMA= output force/ input force, 5/2
</span>
I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
Answer:
If it is moving 34 m/s it will take 100 seconds, or 1:40 to reach 3400 meters.
Explanation:
I found this answer by dividing 3400 by 34 and converting seconds to minutes
Answer:
same problem is here also bro i cannot find this plz help anyone
