Answer:
Explained below
Explanation:
To explain this, let's consider a tennis ball being launched from the top of a very high building.
Now, if the tennis ball is launched horizontally without any upward angle but with an initial velocity of 10 m/s. In this motion, If there is no gravity, the tennis ball would continue in motion at that same speed of 10 m/s in the horizontal direction. However, in reality, gravity causes the tennis ball to accelerate downwards at a rate of 9.8 m/s for every second. This implies that the vertical velocity component is changing at the rate of 9.8 m/s every second.
Thus, after 1 second, horizontal velocity component will remain 10 m/s and vertical component will be 9.8 m/s × 1 = 9.8 m/s downwards.
Also, after 2 seconds, the vertical velocity component will remain 10 m/s, however the vertical component will now be 9.8 × 2 = 19.6 m/s downwards.
Same procedure is repeated as t increases by 1 second.
Explanation:
The formula we are going to use is
Pressure = F/A
Elephant:
First, we need to convert weight into newtons.
1kg=9.8 newtons, so 2800kg × newtons = 27440newtons
For 4 feet= 200×4= 800cm^2
Convert the area to meter squared using the following:
1 centimeter squared = 0.0001 meters squared
800cm^2×0.0001= 0.08m^2
Pressure=F/A
Pressure= 27440/0.08
The pressure exerted on the ground by the elephant is 343000 Pascals.
Vulture:
12kg×9.8=117.6newtons
for 2 feet= 2.0×2=4cm^2
4×0.0001=0.0004m^2
117.6/0.0004= 294000 Pascals
To compare the pressure, just do a ratio of the elephant's pressure to vulture's pressure.
343000/294000≈ 1.17
So the pressure is about 1 times bigger.
Keep in mind that the elephant has 4 feet, which help to increase the area which in turn decrease the pressure.
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Answer:
work output is always less than work input - the ratio is less than 1.
Explanation:
This principle comes from the fact that a machine or system cannot produce more work than is supplied to it, because this would violate the energy conservation law (work is a type of mechanical energy).
In theoretical machines called "ideal machines" the input work is the same as the output work, but these machines are only theoretical because in real applications there is always some type of energy loss, either in heat produced by a machine or processes for its operation, for this reason the output work is always less than the input work.
Regarding the ratio work output to work input:
because work input WI is always greater than work output WO.