A bowling ball has an initial momentum of +30 kg m/s and hits a stationary bowling pin. After the collision, the bowling ball le
1 answer:
Answer:
+17 kg m/s
Explanation:
Question is missing. Found it on google:
"<em>What is the magnitude of the final momentum of the bowling pin if it has a mass of 1.5 kg</em>?"
Solution:
we can solve this problem by using the law of conservation of momentum. In fact, the total momentum of the system must be conserved, so we can write:
where
is the momentum of the ball before the collision
is the momentum of the pin before the collision (zero because the pin is stationary)
is the momentum of the ball after the collision
is the momentum of the pin after the collision
Solving the equation for , we find:
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Explanation:
Given that,
The slope of the ramp,
Mass of the box, m = 60 kg
(a) Distance covered by the truck up the slope, d = 300 m
Initially the truck moves with a constant velocity. We know that the net work done on the box is equal to 0 as per work energy theorem as :
u and v are the initial and the final velocity of the truck
(b) The work done on the box by the force of gravity is given by :
Here,
W = -24550.13 J
(c) What is the work done on the box by the normal force is equal to 0 as the angle between the force and the displacement is 90 degrees.
(d) The work done by friction is given by :
Hence, this is the required solution.
Answer:
1.648 m/s
Explanation:
1 revolution equals 2pi radians.
Calculate the angular velocity by taking 2pi x v, then divide by 60 seconds.
To convert this to m/s, simply take this answer and multiply it by 0.305m (a.k.a. the radius of the circle).
