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2 years ago

14

I need helpon science ASAP will bive brainlist

1 answer:

frosja888 [35]2 years ago

3 0

Answer:

1

Explanation:

it is a trench so if they went together then they would rise up but if they missed then it would create a hole

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Sometimes voltage is also called A. electrical force. B. electrical potential. C. electrical resistance. D. electrical field ene

Oliga [24]

Voltage<span>, </span>also called<span> electromotive force, is a quantitative expression of the potential difference in charge between two points in an electrical field.

So ACTUALLY an "electromotive force", but of your answer choices.

D. Electrical Field Energy
</span>

7 0

2 years ago

Read 2 more answers

Perform the following operation and express the answer in scientific notation. 7.0x10^3x1.1x10^7

dimulka [17.4K]

Answer:

The answer is: $7.7\times10^{10}$

Explanation:

Scientific notation is of the kind: $a.bc\times10^{x}$

The given calculation:

$7.0\times10^{3}\times1.1\times10^{7}=(7\times1.1)\times10^{(3+7)}$

$=7.7\times10^{10}$

Therefore, the answer in scientific notation is: $7.7\times10^{10}$

4 0

2 years ago

How many deciliters are in 8.12 decaliters?

statuscvo [17]

812 deciliters is the correct answer that you are looking for.

8 0

2 years ago

Read 2 more answers

makkiz [27]

Explanation:

For number 9. the answer is 668.23255199999

For number 10. the answer is 1029.7634968

For number 11. the answer is 856.7084

For number 12. the answer is 10.37559999999

4 0

2 years ago

A helium-filled weather balloon has a volume of 793 L at 16.9°C and 759 mmHg. It is released and rises to an altitude of 4.05 km

mariarad [96]

<h3>Answer:</h3>

1082.96 L

<h3>Explanation:</h3>

We are given;

Initial volume of helium gas, V1 = 793 L
Initial temperature, T1 = 16.9°C

But, K = °C + 273.15

Thus, initial temperature, T1 is 290.05 K
Initial pressure, P1 = 759 mmHg
New pressure at 4.05 km, P2 = 537 mmHg
New temperature at 4.05 km, T2 = 7.1 °C

= 280.25 K

Assuming we are required to calculate the new volume at the height of 4.05 km

We are going to use the combined gas law.

According to the combined gas law;

$\frac{P1V1}{T1}=\frac{P2V2}{T2}$

Rearranging the formula;

$V2=\frac{P1V1T2}{P2T1}$

$V2=\frac{(759mmHg)(793L)(280.25K)}{(537mmHg)(290.05K)}$

$V2=1082.96L$

Therefore, the new volume of the balloon at the height of 4.05 km is 1082.96 L

6 0

2 years ago