Bromide ions donates an electron in redox reactions.
<u>Explanation:</u>
- In these redox reactions, the halide ions like bromide donates a pair of electrons and acts as a reducing agents, but itself gets oxidized to bromine.
- In this process, the oxidation state of bromide ion is increased from -1 to 0 oxidation state, that is Br⁻ (-1) to Br₂ (0), thus reduces the compound and oxidizes by itself.
- Bromide ion is a strong reducing agent, thereby reduces sulfuric acid which changes to sulfur di oxide, but this doesn't happen in the case of chloride and fluoride ions as they are not having that much capacity like bromide and iodide ions.
Carbon dioxide is the other product created.
Answer:
The correct answer is option e.
Explanation:
The lead acid battery consists lead as an anode and lead oxide as a cathode. Both the electrodes are suspended in dilute sulfuric acid which act as an electrolyte.
At anode: Oxidation
At cathode: Reduction
Answer:
Density of aluminum is 2.699 g/cm^3
Explanation:
Density of a given material can be defined as the mass of the substance present in a unit volume. Mathematically it can be expressed as:
Units: g/cm^3 or kg/m^3
Aluminum (Al) is one the lightest element and is known to have a density of 2.699 g/cm^3
Answer:
The answer is: <u>Al2O3</u>
Explanation:
The data they give us is:
To find the empirical formula without knowing the grams of the compound, we find it per mole:
- 0.545 g Al * 1 mol Al / 27 g Al = 0.02 mol Al
- 0.485 g O * 1 mol O / 16 g O = 0.03 mol O
Then we must divide the results obtained by the lowest result, which in this case is 0.02:
- 0.02 mol Al / 0.02 = 1 Al
- 0.03 mol O / 0.02 = 1.5 O
Since both numbers have to give an integer, multiply by 2 until both remain integers:
Now the answer is given correctly:
