Answer
A. It changes the rate, R
Explanation
When we change the concentration of the reactants in a chemical reaction, it affects the rate of reaction that happens in the process. Typically, the rate of reaction will decrease with time if the concentration of the reactants decreases because the reactants will be converted to products. Similarly, the rate of reaction will increase when the concentration of reactants are increased.
The full question is shown in the image attached
Answer:
See explanation
Explanation:
In naming an alkane, the first thing we do is to obtain the parent chain by counting the number of carbon atoms in the chain.
When we obtain that, then we identify the substituents and number them in such a way that they have the lowest numbers. The compounds shown have the following names according to the order in which the structures appear in the image attached;
1. 2-methyl propane
2. 2,4-dimethyl heptane
3. 2,2,3,3-tetramethyl butane
4. 5-ethyl-2,4-dimethyl octane
<u>Question:</u>
For the cell constructed from the hydrogen electrode and metal-insoluble salt electrode, B) calculate the mean activity coefficient for 0.124 b HCl solution if E=0.342 V at 298 K
<u>Answer:</u>
The mean activity coefficient for HCl solution is 0.78.
<u>Explanation:</u>
Activity coefficient is defined as the ratio of any chemical activity of any substance with its molar concentration. So in an electrochemical cell, we can write activity coefficient as γ. The equation for determining the mean activity coefficient is
![E=E_{0}-0.0514 \mathrm{V} \ln \gamma](https://tex.z-dn.net/?f=E%3DE_%7B0%7D-0.0514%20%5Cmathrm%7BV%7D%20%5Cln%20%5Cgamma)
As we know that
= 0.22 V and E = 0.342 V, the equation will become
![0.342 V+0.0514 V \ln (0.124)=0.22 V-0.0514 V \ln \gamma](https://tex.z-dn.net/?f=0.342%20V%2B0.0514%20V%20%5Cln%20%280.124%29%3D0.22%20V-0.0514%20V%20%5Cln%20%5Cgamma)
![0.342 V-0.222 V=-0.0514 V(\ln \gamma+\ln 0.124)](https://tex.z-dn.net/?f=0.342%20V-0.222%20V%3D-0.0514%20V%28%5Cln%20%5Cgamma%2B%5Cln%200.124%29)
![0.12 \mathrm{V}=-0.0514 \mathrm{V}(\ln \gamma+\ln 0.124)](https://tex.z-dn.net/?f=0.12%20%5Cmathrm%7BV%7D%3D-0.0514%20%5Cmathrm%7BV%7D%28%5Cln%20%5Cgamma%2B%5Cln%200.124%29)
![\frac{0.12}{0.0514}=-\ln (0.124 \gamma)](https://tex.z-dn.net/?f=%5Cfrac%7B0.12%7D%7B0.0514%7D%3D-%5Cln%20%280.124%20%5Cgamma%29)
![-2.3346=\ln (0.124 \gamma)](https://tex.z-dn.net/?f=-2.3346%3D%5Cln%20%280.124%20%5Cgamma%29)
![e^{-2.3346}=0.124 \gamma](https://tex.z-dn.net/?f=e%5E%7B-2.3346%7D%3D0.124%20%5Cgamma)
![0.0968=0.124 \gamma](https://tex.z-dn.net/?f=0.0968%3D0.124%20%5Cgamma)
![\gamma=\frac{0.0968}{0.124}=0.78](https://tex.z-dn.net/?f=%5Cgamma%3D%5Cfrac%7B0.0968%7D%7B0.124%7D%3D0.78)
So, the mean activity coefficient is 0.78.
Fe(s) + CuSO4(aq) -> Cu(s) + FeSO4(aq) is the answer if you get it in advance...