Because it’s hard snow that can kill you
Either 175 N or 157 N depending upon how the value of 48° was measured from.
You didn't mention if the angle of 48° is from the lug wrench itself, or if it's from the normal to the lug wrench. So I'll solve for both cases and you'll need to select the desired answer.
Since we need a torque of 55 N·m to loosen the nut and our lug wrench is 0.47 m long, that means that we need 55 N·m / 0.47 m = 117 N of usefully applied force in order to loosen the nut. This figure will be used for both possible angles.
Ideally, the force will have a 0° degree difference from the normal and 100% of the force will be usefully applied. Any value greater than 0° will have the exerted force reduced by the cosine of the angle from the normal. Hence the term "cosine loss".
If the angle of 48° is from the normal to the lug wrench, the usefully applied power will be:
U = F*cos(48)
where
U = Useful force
F = Force applied
So solving for F and calculating gives:
U = F*cos(48)
U/cos(48) = F
117 N/0.669130606 = F
174.8537563 N = F
So 175 Newtons of force is required in this situation.
If the 48° is from the lug wrench itself, that means that the force is 90° - 48° = 42° from the normal. So doing the calculation again (this time from where we started plugging in values) we get
U/cos(42) = F
117/0.743144825 = F
157.4390294 = F
Or 157 Newtons is required for this case.
Answer:
The principal hair fiber used to produce textile fabrics is sheep's wool. In wild sheep, the wool is a short, soft underlayer protected by longer, coarser hair. ... Fur fibers from animals such as mink and beavers are sometimes blended with other hairs to spin luxury yarns but are most often found as fur pelts.
Answer:
Object 2 has the larger drag coefficient
Explanation:
The drag force, D, is given by the equation:
Object 1 has twice the diameter of object 2.
If 
Area of object 2, 
Area of object 1:
Since all other parameters are still the same except the drag coefficient:
For object 1:
For object 2:
Since the drag force for the two objects are the same:
Obviously from the equation above, c₂ is larger than c₁, this means that object 2 has the larger drag coefficient
Answer:
2.25m/s
Explanation:
wavelength=4.5m
period=2sec
frequency= 1/period
=1/2
speed= wavelength×wave frequency
=4.5×1/2
=2.25 m/s
so, none of the options are correct
