Grade 1: Stretching or slight tearing of the ligament with mild tenderness, swelling and stiffness. The ankle feels stable and it is usually possible to walk with minimal pain.
Grade 2: A more severe sprain, but incomplete tear with moderate pain, swelling and bruising. Although it feels somewhat stable, the damaged areas are tender to the touch and walking is painful.
Grade 3: This is a complete tear of the affected ligament(s) with severe swelling and bruising. The ankle is unstable and walking is likely not possible because the ankle gives out and there is intense pain.
source - https://www.rushcopley.com/health/physician-articles/varying-degrees-of-ankle-sprains/
Hello,
<u>Solution for A:</u>
Force = 3.00N
Mass = 0.50 Kgs
Time = 1.50 Seconds
According to newton's second law of motion;
Force = Mass times Acceleration(a)
3.00 = 0.50 * a
a = 3.00/0.50 = 6.00 m/s^2
We know that acceleration = Velocity / time
So Velocity = time * acceleration = 1.50 * 6 = 9.00 m/s^2
<u>Solution for B:</u>
The net force = 4.00N - 3.00N = 1.00N to the left
Force = 1.00N
Mass = 0.50Kg
Time = 3.00 Seconds
Again; F = MA (Where F is force, M is mass and A is acceleration)
1.00N = 0.5 * A
A = 1/0.5 = 2 m/s^2
Velocity = Acceleration * Time = 2 * 3 = 6 m/s
Answer:
D
Explanation:
The least of the conditions that can result in fossilization would be <u>when an organism is a prey to several species.</u>
Fossils are remains or traces of organisms that have been geological preserved and a prey is an organism that is often hunted and serves as food to bigger organisms. <em>When an organism is eaten, the probability of it becoming a fossil becomes low. Unless such an organism is usually partially eaten by predators, there would not be any remains, let alone being fossilized.</em>
The correct option is D.
Answer:
Explanation:
doubling the speed will have a greater impact on kinetic energy as KE is a product of mass and the square of velocity.
KE = ½mv²
Base KE = ½(0.005)2.0² = 0.01 J
doubling the mass
KE = ½(0.010)2.0² = 0.02 J
doubling the velocity
KE = ½(0.005)4.0² = 0.04 J
