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Studentka2010 [4]
3 years ago
11

you push a ball to star it rolling along a "perfectly frictionless" surface. How far will the ball roll

Physics
1 answer:
-BARSIC- [3]3 years ago
6 0
Technically, it should roll forever.
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Write an equation for the nth term of the arithmetic sequence: 64, 78, 92, 106, ...
Anna [14]

If  64  is term #1 of the sequence,
then the general term is
                                      <em> T(n) = 50 + 14n </em>.


4 0
4 years ago
A toy car attached to a rope is traveling around in a circle. It makes 4 laps in 12s.What is the angular velocity of the toy car
umka21 [38]

Answer:

2.09 rad/s

Explanation:

Given that,

A toy car makes 4 laps in 12 s.

We need to find the angular velocity of the toy car. We need to find the angular velocity of the toy car.

4 laps = 25.13 rad

So,

v=\dfrac{25.13\ rad}{12\ s}\\\\v=2.09\ rad/s

So, the angular velocity of the toy car is 2.09 rad/s.

3 0
3 years ago
PRACTICE ANOTHERA rabbit is hopping along at an approximately constant speed of 4.2 m/s. The rabbit passes a crouched cat ready
V125BC [204]

Answer:

16.8 seconds

Explanation:

Given that:

Constant speed of rabbit = 4.2 m/s

Initial Velocity (u) of cat = 0

Acceleration (a) of cat = 0.5 m/s²

Time it takes cat to catch rabbit ;

Using the relation:

Distance moved by rabbit (Dr) :

Dr = speed * time ; Dr = 4.2t

Distance moved by Cat (Dc) :

Dc = ut + 0.5at^2

Dc = 0 + 0.5at^2

Hence, Cat will catch rabbit when Dr = Dc

4.2t = 0.5at^2

4.2t = 0.5(0.5)t^2

4.2t = 0.25t^2

Divide both sides by t

4.2 = 0.25t

t = 4.2 / 0.25

t = 16.8 seconds

Hence, the cat will catch the rabbit after 16.8 seconds

5 0
3 years ago
A pizza parlor is considering adding taco pizza and Hawaiian pizza to its
tia_tia [17]

Answer: 79

Explanation:

7 0
3 years ago
Read 2 more answers
A charged particle moving through a magnetic field at right angles to the field with a speed of 24.7 m/s experiences a magnetic
Sunny_sXe [5.5K]

Answer:

Explanation:

let the charge is q. velocity, v = 24.7 m/s

magnetic force, F = 2.38 x 10^-4 N

Let the magnetic field is B.

Velocity, v' = 5.64 m/s

angle, θ = 21.2°

The force experienced by a charged particle placed in a magnetic field is given by

F = q x v x B x Sinθ

in first case

2.38 x 10^-4 = q x 24.7 x B x Sin 90 .... (1)

in second case

F = q x 5.64 x B x Sin 21.2°      .... (2)

Divide equation (2) by equation (1), we get

\frac{F}{2.38\times 10^{-4}}=\frac{5.64\times Sin 21.2}{24.7\times Sin 90}

F = 1.97 x 10^-5 N

7 0
4 years ago
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