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3 years ago

Need help please !!!! Hurry

Physics

2 answers:

Naily [24]3 years ago

8 0

Answer:

Explanation:

frequency and wavelength are inverses, so since this has the smallest wavelength it has the highest frequency. The smaller the wavelength, the more waves (more/high frequency) fit in a certain area in comparison to larger wavelengths fit fewer waves (less frequent).

s2008m [1.1K]3 years ago

3 0

Answer:

Explanation:

Waves that are squished have higher frequency. It has short wavelength.

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A 2 kg block is pushed by an external force against a spring with spring constant 131 N/m until the spring is compressed by 2.1

Andrej [43]

Answer:

d = 19.92 m

Explanation:

As in this exercise there is friction we must use the relationship between work and energy

W = ΔEm

Look for energy in two points

Initial. Fully compressed spring

Em₀ = $K_{e}$ = ½ k x²

Final. When the block stopped

$Em_{f}$ = 0

Let's look for the work of the rubbing force

W = fr d cos θ

Since rubbing is always contrary to movement, θ = 180

W = - fr d

Let's use Newton's second Law, to find the force of friction

Y Axis

N- w = 0

N = mg

The equation for the force of friction is

fr = μ N

fr = μ mg

We substitute in the work equation

W = - μ m g d

We write the relationship of work and energy

-μ m g d = 0 - ½ k x²

d = ½ k x² / μ m g

Let's calculate

d = ½ 131 2.1 2 / (0.74 2 9.8)

d = 19.92 m

7 0

4 years ago

Force F=2.0N i - 3.0N k acts on a pebble with position vectorr=0.50m j - 2.0m k relative to the origin. In unit vector notation,

klasskru [66]

Answer with Explanation:

We are given that

Force acts on a pebble= $2\hat{i}-3\hat{k}$ N

Position vector= $r=0.5\hat{j}-2\hat{k}$ m

a.We have to find the resulting torque on the pebble about origin.

Torque= $r\times F$

Substitute the values then we get

$Torque= (0.5j-2k)\times (2i-3k)$

Torque= $-k-1.5i-4j$ N-m

By using $i\times j=k,j\times k=i,k\times i=j,j\times i=-k,k\times j=-i,i\times k=-j,i\times i=j\times j=k\times k=0$

b. $r=2i-3k$

$r-r_1=(0.5j-2k)-(2i-3k)=-2i+0.5j+k$

Torque about point (2,0,-3)

$\tau=(-2i+0.5j+k)\times (2i-3k)$

$\tau=-6j-k-1.5i+2j=-1.5i-4j-k$ N-m

6 0

3 years ago

Say we have two objects. Object A and B are the same size and shape. However object B is much heavier than Object A. If i were t

Nina [5.8K]

Answer:

Two objects that are the same volume will displace the same amount of water even if they have different masses.

3 0

2 years ago

Light rays in a material with index of refrection 1.29 1.29 can undergo total internal reflection when they strike the interface

deff fn [24]

Answer:

The second material's index of refraction is 1.17.

Explanation:

Given that,

Refractive index of the material, n = 1.29

Critical angle is 65.9 degrees.

We need to find the second material's index of refraction. We know that at critical angle of incidence, angle of refraction is equal to 90 degrees. Using Snell's law as:

$n_1\sin \theta_c=n_2\sin (90)\\\\n_2=n_1\sin \theta_c\\\\n_2=1.29\times \sin (65.9)\\\\n_2=1.17$

So, the second material's index of refraction is 1.17.

7 0

3 years ago

For which pair of objects would adding the same amount of electrons to each object result in a decrease in the electric force?

Licemer1 [7]

The answer is A... hope this helps

4 0

3 years ago

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