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Diano4ka-milaya [45]
3 years ago
10

Need help please !!!! Hurry

Physics
2 answers:
Naily [24]3 years ago
8 0

Answer:

4

Explanation:

frequency and wavelength are inverses, so since this has the smallest wavelength it has the highest frequency. The smaller the wavelength, the more waves (more/high frequency) fit in a certain area in comparison to larger wavelengths fit fewer waves (less frequent).

s2008m [1.1K]3 years ago
3 0

Answer:

4

Explanation:

Waves that are squished have higher frequency. It has short wavelength.

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What are two ways in which the suns energy can be captured and used?
My name is Ann [436]

The oldest way ... the way we've been using as long as we've been
walking on the Earth ... has been to use plants.  Plants sit out in the
sun all day, capturing its energy and using it to make chemical compounds. 
Then we come along, cut the plants down, and eat them.  Our bodies
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and then we use the energy to walk around, sing, and play video games.  

Another way to capture the sun's energy is to build a dam across a creek
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A modern, recent new way to capture some of the sun's energy is to use
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7 0
3 years ago
Read 2 more answers
A static charge that is produced by a nearby objet is an?
Wittaler [7]
I believe that it is electric field
7 0
3 years ago
What is the calculation for elastic potential?
grin007 [14]
Elastic potential energy is equal to the force times the distance of movement. Elastic potential energy = force x distance of displacement. Because the force is = spring constant x displacement, then the Elastic potential energy = spring constant x displacement squared.
3 0
3 years ago
A mass is oscillating with amplitude A at the end of a spring.
Dmitry_Shevchenko [17]

A) x=\pm \frac{A}{2\sqrt{2}}

The total energy of the system is equal to the maximum elastic potential energy, that is achieved when the displacement is equal to the amplitude (x=A):

E=\frac{1}{2}kA^2 (1)

where k is the spring constant.

The total energy, which is conserved, at any other point of the motion is the sum of elastic potential energy and kinetic energy:

E=U+K=\frac{1}{2}kx^2+\frac{1}{2}mv^2 (2)

where x is the displacement, m the mass, and v the speed.

We want to know the displacement x at which the elastic potential energy is 1/3 of the kinetic energy:

U=\frac{1}{3}K

Using (2) we can rewrite this as

U=\frac{1}{3}(E-U)=\frac{1}{3}E-\frac{1}{3}U\\U=\frac{E}{4}

And using (1), we find

U=\frac{E}{4}=\frac{\frac{1}{2}kA^2}{4}=\frac{1}{8}kA^2

Substituting U=\frac{1}{2}kx^2 into the last equation, we find the value of x:

\frac{1}{2}kx^2=\frac{1}{8}kA^2\\x=\pm \frac{A}{2\sqrt{2}}

B) x=\pm \frac{3}{\sqrt{10}}A

In this case, the kinetic energy is 1/10 of the total energy:

K=\frac{1}{10}E

Since we have

K=E-U

we can write

E-U=\frac{1}{10}E\\U=\frac{9}{10}E

And so we find:

\frac{1}{2}kx^2 = \frac{9}{10}(\frac{1}{2}kA^2)=\frac{9}{20}kA^2\\x^2 = \frac{9}{10}A^2\\x=\pm \frac{3}{\sqrt{10}}A

3 0
3 years ago
two cars start at the same point and drive in a straight line for 5km. At the end of the drive their distances are the same but
Anna11 [10]

A 'displacement' always consists of a magnitude and a direction.  The two cars you just described have displacements with the same magnitude ... 5 km.  But if they didn't both drive in the same direction, then their displacements are different.

Remember:

-- 10 m/s² up and 10 m/s² down are different accelerations

-- 30 mph East and 30 mph West are the same speed but different velocity.

-- 5 km North and 5 km South are the same distance but different displacement.

7 0
3 years ago
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