The focal point of a concave mirror is IN FRONT OF the mirror.
Answer:
The answer is
<h2>56,000 kgm/s</h2>
Explanation:
The momentum of an object can be found by using the formula
<h3>momentum = mass × velocity</h3>
From the question
m = 1400 kg
v = 40 m/s
We have
momentum = 1400 × 40
We have the final answer as
<h3>56,000 kgm/s</h3>
Hope this helps you
The work done on the mass is approximately 1J
<h3>How to calculate work done on mass</h3>
From the question, we are to determine the work done on the mass
The work done can be calculated from the formula for Potential energy
Work done = P.E = mgh
Where m is the mass
g is the acceleration due to gravity (g = 10 m/s²)
h is the height
From the question,
m = 2.0 kg
h = 0.050 m
Putting the values into the question, we get
Work done = 2.0 × 10 × 0.050
Work done = 1 J
Hence, the work done on the mass is approximately 1J
Learn more on how to calculate work done here: brainly.com/question/14460830
An air-mass thunderstorm, also called an "ordinary", "single cell", or "garden variety" thunderstorm, is athunderstorm that is generally weak and usually not severe. ... The energy needed for these storms to form comes in the form of insolation, or solar radiation.
Answer:
a) Electric potential = 853 V
b) Electron speed at point B, if at Point A, the speed were zero = 1.732 × 10⁷ m/s
Explanation:
For an electron moving in an electric field with potential V,
Work done = qV where q is the charge on the electron
And the Work done is equal to the change in kinetic energy of the electron
qV = m(v₂² - v₁²)/2
V = m(v₂² - v₁²)/2q
q = 1.602 × 10⁻¹⁹C
m = 9.11 × 10⁻³¹ kg
v₁= 10⁷ m/s
v₂ = 2 × 10⁷ m/s
Putting these values in for the variables and solving
V = 853 V
b) If the electron started from rest,
qV = mv²/2
v = √(2qV/m) =√((2 × (1.602 × 10⁻¹⁹) × 853)/(9.11 × 10⁻³¹)) = 1.732 × 10⁷ m/s