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agasfer [191]
3 years ago
6

The diagram below shows a group of water molecules.

Chemistry
2 answers:
Natali5045456 [20]3 years ago
8 0

Just took it, Hydrogen bonds

lukranit [14]3 years ago
8 0

Answer: B: Hydrogen bonds

Explanation: Hydrogen bond is a bond formed between a hydrogen atom and a electronegative atom such as fluorine, oxygen or nitrogen. It is a strong bond.

Ionic bond is formed by the transfer of electrons between metals and non metals.

London dispersion force is a temporary attractive force that results when the electrons in adjacent atoms occupy positions that make the atoms form temporary dipoles.

Dipole induced dipole interactions is a weak attraction that results when a polar molecule induces a dipole in a neighboring atom or a non polar molecule by disturbing the arrangement of electrons.

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What is the distinction between magma and lava​
BabaBlast [244]

Answer:

Scientists use the term magma for molten rock that is underground and lava for molten rock that breaks through the Earth's surface.

7 0
2 years ago
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Calculate the hydroxide ion concentration [OH-] for a solution with a pH of 6.10
nalin [4]

There are different formula you need to keep in mind when solving for [OH-]

Given that pH = 6.10

pH + pOH = 14

6.10 + pOH = 14

pOH = 7.9

[OH-] = 10^(-pOH)

[OH-] = 10^(-7.9)

[OH-] = 0.000000013

[OH-] = 1.3 x 10^-8


<h2><u>Answer: [OH-] = 1.3 x 10^-8</u></h2>
4 0
3 years ago
Lab report calorimetry and specific heat <br> HELP PLZ
dolphi86 [110]

Explanation:

Specific heat capacity can be calculated using the following equation: q = mc∆T In the equation q represents the amount of heat energy gained or lost (in joules ), m is the mass of the substance (in grams), c is the specific heat capacity of the substance (in J/g °C), and ∆T is the temperature change of the substance 

8 0
3 years ago
What is the freezing point of a solution of 498mL of water (solute) dissolved in 2.50 L of ethanol (solvent), C2H5OH? The densit
jok3333 [9.3K]

Answer:

Freezing T° of solution is -142.4°C

Explanation:

This excersise is about colligative properties, in this case freezing point depression,

ΔT = Kf . m . i

Where ΔT = Freezing T° of solvent - Freezing T° of solution

Kf = Cryoscopic constant

m = mol/kg (molality)

i = Number of ions dissolved.

Water is not ionic, so i = 1

Let's find out m.

We determine mass of water, by density

498ml . 1 g/mL = 498 g

We convert the mass of water to moles → 498 g . 1mol/18g = 27.6 moles

We determine mass of solvent by density

2500 mL . 0.789 g/mL = 1972.5 g

Notice, we had to convert L to mL to cancel units.

1 cm³ = 1 mL

We convert the mass from g to kg → 1972.5 g . 1kg /1000g = 1.97kg

We determine m = mol/kg → 27.6mol / 1.97kg = 13.9 m

Kf for ethanol is: 1.99 °C/m

Freezing T° for ethanol is: -114.6°C

We replace at formula: - 114.6°C - Freezing T° solution = 1.99 °C/m . 13.9 m . 1

- 114.6°C - Freezing T° solution = 27.8 °C

- Freezing T° solution  = 27.8°C + 114.6°C

Freezing T° Solution = - 142.4 °C

7 0
2 years ago
Heeellllpppp ASAP ......
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I saw B, he vented SUS

Explanation:

Iodoethane Is the answer.

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