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2 years ago

Gary needs to move a chair that is 20 pounds at a distance of 5 feet. How much work will he need to produce?

Physics

2 answers:

Bas_tet [7]2 years ago

8 0

answer- 100 ft-lbs

Hope I helped

tangare [24]2 years ago

3 0

<h2>Hello!</h2>

The answer is:

The answer is the first option, 100 ft-lbs.

To calculate the work done by an object over a distance, we need to multiply the applied force by the amount of movement (distance).

So, to calculate the work that Gary needs to do to move the chair, we need to use the following equation:

$Work=Force*Distance$

We are given,

$Force=20lb\\Distance=5ft$

$Work=F*D\\Work=(20lb)*(5ft)=100ft-lbs$

Hence, the answer is the first option, 100 ft-lbs.

Have a nice day!

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A bowling ball traveling with constant speed hits the pins at the end of a bowling lane 16.5 m long. The bowler hears the sound

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Answer:

$5.997m/s$

Explanation:

We were told to calculate the speed of the ball,

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And we know that the sound of the ball hitting the pins is at 2.80 s after the ball is released from his hands.

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t= time of hearing - time the sound travels

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andrey2020 [161]

Answer:

The small car and the truck experience the same average force.

Explanation:

Here we need to remember two of Newton's laws.

The second one says that:

F = m*a

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And the third one says that;

"If an object A exerts a force on object B, then object B must exert a force of equal magnitude and opposite direction back on object A"

From the third law, if the car experiences a force F due to the impact with the truck, then the truck experiences the same force F due to the impact.

But this seems odd, because we would expect to see the car being more affected by the impact, right?

Well, this is explained by the second law.

Suppose that the mass of the car is m, and the mass of the truck is M.

such that M > m

Then for the small car we have:

F = m*a

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F = M*a'

Because the force is the same for both of them, we can write:

m*a = M*a'

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because M > m, then M/m > 1.

This means that the acceleration that the car experiences is larger than the acceleration for the truck, and this is why we would see that the car seems more affected by the impact, regardless of the fact that both vehicles experience the same force in the impact.

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