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AveGali [126]
3 years ago
6

Gary needs to move a chair that is 20 pounds at a distance of 5 feet. How much work will he need to produce?

Physics
2 answers:
Bas_tet [7]3 years ago
8 0

answer- 100 ft-lbs

Hope I helped

tangare [24]3 years ago
3 0
<h2>Hello!</h2>

The answer is:

The answer is the first option, 100 ft-lbs.

<h2>Why?</h2>

To calculate the work done by an object over a distance, we need to multiply the applied force by the amount of movement (distance).

So, to calculate the work that Gary needs to do to move the chair, we need to use the following equation:

Work=Force*Distance

We are given,

Force=20lb\\Distance=5ft

Work=F*D\\Work=(20lb)*(5ft)=100ft-lbs

Hence, the answer is the first option, 100 ft-lbs.

Have a nice day!

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Neko [114]

... the angular tilt of the Earth's position on its axis relative to the sun


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3 years ago
A 65.0 kg skier slides down a 37.20 slope with mu = 0.107.<br><br>What is the friction force?
zmey [24]

Answer:

54.3N

Explanation:

The normal force is perpendicular to the slope, so:

Normal Force = cos(37.2)(9.8*65).......507.39N

F(friction)=mu*F(normal)

F(friction)=(0.107)(507.39)

F(friction)=54.3N

3 0
2 years ago
A pendulum of length L=36.1 cm and mass m=168 g is released from rest when the cord makes an angle of 65.4 degrees with the vert
pychu [463]

(a) -0.211 m

At the beginning the mass is displaced such that the length of the pendulum is L = 36.1 cm and the angle with the vertical is

\theta=65.4^{\circ}

The projection of the length of the pendulum along the vertical direction is

L_y = L cos \theta = (36.1 cm)(cos 65.4^{\circ})=15.0 cm

the full length of the pendulum when the mass is at the lowest position is

L = 36.1 cm

So the y-displacement of the mass is

\Delta y = 15.0 cm - 36.1 cm = -21.1 cm = -0.211 m

(b) 0.347 J

The work done by gravity is equal to the decrease in gravitational potential energy of the mass, which is equal to

\Delta U = mg \Delta y

where we have

m = 168 g = 0.168 kg is the mass of the pendulum

g = 9.8 m/s^2 is the acceleration due to gravity

\Delta y = 0.211 m is the vertical displacement of the pendulum

So, the work done by gravity is

W=(0.168 kg)(9.8 m/s^2)(0.211 m)=0.347 J

And the sign is positive, since the force of gravity (downward) is in the same direction as the vertical displacement of the mass.

(c) Zero

The work done by a force is:

W=Fd cos \theta

where

F is the magnitude of the force

d is the displacement

\theta is the angle between the direction of the force and the displacement

In this situation, the tension in the string always points in a radial direction (towards the pivot of the pendulum), while the displacement of the mass is tangential (it follows a circular trajectory): this means that the tension and the displacement are always perpendicular to each other, so in the formula

\theta=90^{\circ}, cos \theta = 0

and so the work done is zero.

5 0
3 years ago
¿Qué nombre recibe un electrón que abandona el espacio interno del átomo dirigiéndose al exterior del átomo?
Alenkinab [10]

Answer:

i dont speack spanish sorry

Explanation: agian sorry

7 0
2 years ago
You drop a rock from rest from the top of a tall building.1)how far has the rock fallen in 2.60 s?
Bess [88]
Answer:
distance = 33.124 meters

Explanation:
To solve this question, we will use one of the equations of motion which is:
s = ut + 0.5a * t^2
where:
s is the distance that we want to get
u is the initial velocity = 0
a is the acceleration due to gravity = 9.8 m/sec^2
t is the time = 2.6 sec

Substitute with the givens in the equation to get the distance as follows:
s = ut + 0.5a * t^2
s = (0)(2.6) + 0.5(9.8)(2.6)^2
s = 33.124 meters

Hope this helps :)
7 0
3 years ago
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