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Mrrafil [7]
2 years ago
8

A car dropped from a height of 44 meters fall to a height of zero meters. How fast will the car be traveling as it hits the grou

nd? Assume air resistance is negligible (show all work)
Physics
1 answer:
FinnZ [79.3K]2 years ago
6 0
Vi=0m/s
Vf=?
A=9.81
D=44
T=not needed

Vf^2=Vi^2+2ad
Vf=2ad square rooted
Vf=2(9.81)(44) square root it
Vf=29.3m/s
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Learning Goal: To be able to calculate work done by a constant force directed at different angles relative to displacement
svlad2 [7]

Answer:

Woke done, W = 4156.92 Joules

Explanation:

The work done by the force can be calculated as :

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\theta is the angle between force and the displacement

It is assumed to find the work done for the given parameters i.e.

Force, F = 30 N

Distance travelled, s = 160 m

Angle between force and displacement, \theta=30

Work done is given by :

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W = 4156.92 Joules

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5 0
2 years ago
Along the line connecting the two charges, at what distance from the charge q1 is the total electric field from the two charges
Nostrana [21]

Answer:

r = d (\frac{\sqrt {q_1}}{\sqrt{q_1} + \sqrt{q_2}})

Explanation:

Here two charges are placed at distance "d" apart

now the net value of electric field at some position between two charges will be ZERO

so we will have

electric field due to charge 1 = electric field due to charge 2

E_1 = E_2

Let the position where net field is zero will lie at distance "r" from q1

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now we will have

\frac{(d - r)^2}{r^2} = \frac{q_2}{q_1}

now square root both sides

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now we have

\frac{d}{r} = \sqrt{\frac{q_2}{q_1}} + 1

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r = d (\frac{\sqrt {q_1}}{\sqrt{q_1} + \sqrt{q_2}})

8 0
2 years ago
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gregori [183]

Answer:

E = 0    r <R₁

Explanation:

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