Explanation:
According to the law of conservation of energy
,
Potential energy = kinetic energy
I = 
![mgh = [\frac{1}{2} \times mv^{2}] + [\frac{1}{2} \times (\frac{mr^{2}}{2}) \frac{v^{2}}{r^{2}}]](https://tex.z-dn.net/?f=mgh%20%3D%20%5B%5Cfrac%7B1%7D%7B2%7D%20%5Ctimes%20mv%5E%7B2%7D%5D%20%2B%20%5B%5Cfrac%7B1%7D%7B2%7D%20%5Ctimes%20%28%5Cfrac%7Bmr%5E%7B2%7D%7D%7B2%7D%29%20%5Cfrac%7Bv%5E%7B2%7D%7D%7Br%5E%7B2%7D%7D%5D)
mgh = ![[\frac{1}{2} \times mv^{2}] + [\frac{1}{4} \times mv^{2}]](https://tex.z-dn.net/?f=%5B%5Cfrac%7B1%7D%7B2%7D%20%5Ctimes%20mv%5E%7B2%7D%5D%20%2B%20%5B%5Cfrac%7B1%7D%7B4%7D%20%5Ctimes%20mv%5E%7B2%7D%5D)
v = 7.4 m/s
thus, we can conclude that the translational speed of the cylinder when it leaves the incline is 7.4 m/s.
Question 4 is true, question 5 is B.
Answer:
0.65 kg*m/s and 0.165 kg*m/s
Explanation:
Step one:
given data
mass m= 0.5kg
initial velolcity u=1.3m/s
final velocity v= 0.97m/s
Required
The change in momentum
Step two:
We know that the expression for impulse is given as
Ft= mv
Ft= 0.5*1.3
Ft= 0.65 kg*m/s
The expression for the change in momentum is given as
P= mΔv
substitute
Pt= 0.5*(1.3-0.97)
Pt= 0.5*0.33
Pt=0.165 kg*m/s
C.<span>a stable internal attribution</span>
