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ohaa [14]
3 years ago
11

WHAT IS THE ATOMIC NO OF RUBINIUM[RB]

Chemistry
2 answers:
Zinaida [17]3 years ago
6 0

Rubidium's atomic number is 37.

Hope this helps!

mariarad [96]3 years ago
5 0

Answer:

Atomic number 37!

Explanation:

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How many atoms of hydrogen are in 4Ca(OH)2​
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Explanation:

there are 8 atoms of hydrogen

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2 years ago
Jailah needs a replacement for lithium for a science experiment. She tries silicon, but it does not work. Using what you know ab
pentagon [3]

Answer:

C

Explanation:

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3 years ago
can you guys help me out??? How do different plant structures increase the chances for successful reproduction? Use evidence to
Roman55 [17]

Answer: Different plant structure can increase chances of reproduction by the animals and other living organisms in the ecosystem.

Explanation: Plants like flowers can be pollinated by bees . The bees carry the pollen and this can increase chances of reproduction. Plants like plums that have large seeds can increase chances of reproduction by there fruit falling and rotting so the seed can be forced into soil. Different structures of plants can increase chances of reproduction through the animals, soil around the plant, as well as weather .

4 0
2 years ago
Phosgene, a poisonous gas, when heated will decompose into carbon monoxide and chlorine in a reversible reaction: COCl2 (g) <
Advocard [28]

Answer:

8.08 × 10⁻⁴

Explanation:

Let's consider the following reaction.

COCl₂(g) ⇄ CO (g) + Cl₂(g)

The initial concentration of phosgene is:

M = 2.00 mol / 1.00 L = 2.00 M

We can find the final concentrations using an ICE chart.

     COCl₂(g) ⇄ CO (g) + Cl₂(g)

I       2.00            0            0

C        -x             +x           +x

E    2.00 -x          x             x

The equilibrium concentration of Cl₂, x, is 0.0398 mol / 1.00 L = 0.0398 M.

The concentrations at equilibrium are:

[COCl₂] = 2.00 -x = 1.96 M

[CO] = [Cl₂] = 0.0398 M

The equilibrium constant (Keq) is:

Keq = [CO].[Cl₂]/[COCl₂]

Keq = (0.0398)²/1.96

Keq = 8.08 × 10⁻⁴

4 0
3 years ago
A student experimentally determines the density of a metal cube. The edge length of the cube is measured using calipers. The cub
IgorC [24]

Answer:

10.9%.

Explanation:

The first thing to do in order to solve this question is to Determine the value for the volume of the the cube. This can be done by taking the cube root of the length of the cube;

The volume of the cube = (length of the cube)^3 = length × length × length = 1.72 × 1.72 × 1.72 =( 1.72)^3 = 5.09cm^3.

The next thing you do is to Determine the exponential density, the can be done by using the formula below;

The exponential density = mass/ volume = 55. 786/ 5.09 = 10.96 g/cm^3.

Therefore, the percent error = (true density of the cube - exponential density of the cube)÷ true density of the cube × 100.

Hence, the percent error = 12.30 - 10.96/12.30 × 100 = 10.9%.

8 0
2 years ago
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