Answer:
mCO2= 49.6932 kgCO2
Explanation:
Hello! Let's solve this!
First we propose the balanced equation C3H8 + 5O2 ---> 3CO2 + 4H2O
We see that each mole of C3H8 (propane) we get 3 moles of CO2
From the propane volume we can obtain the grams of propane used.
molpropane = 26.5L * (1000mL / 1L) * (0.621g / 1mL) * (1mol / 44g) = 374.01mol propane
mCO2 = 374.01molC3H8 * (3molCO2 / 1molC3H8) * (44gCO2 / 1molCO2) = 49369.32g * (1kg / 1000g) = 49.6932 kgCO2
mCO2= 49.6932 kgCO2
B. The rate of particle collisions increased with a higher temperature.
An <em>inference </em>is a guess that you make <em>based on an observation</em>. You can’t see the particles, so you are guessing (a) that they exist and (b) that the rate of their collisions increases with a higher temperature.
A, C, and D are all incorrect because they are <em>observations</em> that you make.
Your question has been heard loud and clear.
Uhm , Alkalis are just bases who react with water. In titration we use water also , so we need bases that react with water , and such bases are alkalis.
Alkalis are a type of bases.
Thank you
The correct answer is 1 amu; neutral
Answer:
<em>1 mole is equal to 1 moles NaOH, or 39.99711 grams.</em>
Explanation:
<em>Hope this helps have a nice day :)</em>
