Answer:
The height of the cliff from which the ball was dropped from is 224.4m.
\overline{v}={\frac{\Delta x}{\Delta t}}
Given the data in the question;
Initial velocity of the ball;
Time taken by the ball to reach the ground;
Distance or Height of the cliff from which the ball was thrown from;
To get the height of the Cliff, we use the Second Equation of Motion:
Where s is the distance or height, is the initial velocity, t is the time and a is the acceleration. Since the ball was thrown down from a certain height (cliff), its is now under the influence of gravity. acceleration due to gravity;
Hence, the equation becomes
We substitute the given values into the equation
Therefore, the height of the cliff from which the ball was dropped from is 224.4m
Explanation:
As altitude increases, temperature increases.
The stratosphere is the part of the atmosphere that starts in the tropopause and ends in the estratopause. In the troposphere, the air is close to the Earth surface. The air surface can absorb more sunlight energy than the air, so the Earth surface heats the air. As you go higher, the distance to the Earth surface is higher, so the temperature is lower. The troposphere ends in the tropopause, where this trend changes. In the estratopause, there is a lot of ozone, which absorbs the dangerous UV radiation and converts into heat. That heat warms the air. So the air which is close to the estratopause is warm because of the heat released by the ozone reactions. The tropopause is far from the Earth surface and far from the ozone layer, that’s why it is cold. So the tropopause is cold and the estratopause is warm, which means: the air becomes warmer <span>as you rise above the tropopause until you get to the estratopause.</span>
<span>Energy exists as light, heat, sound, mass, moving objects, gravity, fuel, chemicals, and electricity.</span>
Shadows are the absence of light, they are created when an object blocks light. In other words, shadows are the product of light particles, known as photons. These particles “bounce off” of the object without reaching the other side. Therefore light by itself will not form a shadow.
Answer:
v= 103.5 V; energy =1.65 x 10^-17
Explanation:
the deflected energy eV sin θ
