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Sophie [7]
2 years ago
14

Two friends leave a movie theater and take different busses to the same ice cream shop. one bus takes a longer route driving on

a high-speed highway, while the other takes a shorter route on lower-speed local roads. which friend has the greater displacement?
Physics
1 answer:
irinina [24]2 years ago
8 0

The friend who has the greater displacement is the one who takes the longest path.

<h3>What is displacement?</h3>

The displacement is the shortest distance travelled by the particle. It is the vector quantity which re[presents both the magnitude and direction.

Given, two friends leave a movie theater and take different buses to the same ice cream shop. One bus takes a longer route driving on a high-speed highway, while the other takes a shorter route on lower-speed local roads.

According to the definition. the displacement is neither larger not shorter but it is the shortest distance traveled by the person or particle.

Thus, friend who has longer path has larger displacement.

Learn more about displacement.

brainly.com/question/11934397

#SPJ1

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How will the electrostatic force be changed if the distance between two electric charges is tripled?
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How will the electrostatic force be changed if the distance between two electric charges is tripled?

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The chart below shows the amount of coal mined in four different states of USA in the year 2005.
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The correct answer is <span>Montana.

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3 0
4 years ago
Read 2 more answers
A 0.350 kg block at -27.5°C is added to 0.217 kg of water at 25.0°C. They come to equilibrium at 16.4°C. What is the specific he
Gekata [30.6K]

The specific heat capacity of the block is 508J/kg^{\circ}C

Explanation:

As the block is placed into the water, heat energy is transferred from the water (which is at higher temperature) to the block (which is at lower temperature), until the block and the water are in thermal equilibrium (= same temperature).

Therefore, we can write:

Q_{water}=Q_{block}

Where

Q_{water}=m_w C_w (T_w-T_{eq}) is the heat energy released by the water, where

m_w = 0.217 kg is the mass of the water

C_w = 4186 J/kg^{\circ}C is the water heat specific capacity

T_w = 25.0^{\circ} is the initial temperature of the water

T_{eq}=16.4^{\circ} is the temperature at equilibrium

Substituting,

Q_{water}=(0.217)(4186)(25.0-16.4)=7812 J

Now we can write the heat energy absorbed by the block as

Q_{block}=m_b C_b(T_{eq}-T_b)

where

m_b=0.350 kg is the mass of the block

C_b is the specific heat capacity of the block

T_b = -27.5^{\circ} is the initial temperature of the block

And solving for C_b,

C_b=\frac{Q_{block}}{m_b(T_{eq}-T_b)}=\frac{7812}{(0.350)(16.4-(-27.5))}=508J/kg^{\circ}C

Learn more about specific heat capacity:

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6 0
3 years ago
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