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Westkost [7]
3 years ago
6

How do you draw an ear

Physics
1 answer:
Neporo4naja [7]3 years ago
8 0

Answer:

drawing of ear step by step

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What is the internal energy of 4.50 mol of N2 gas at 253°C? To solve this
Finger [1]

The internal energy of the gas is 49,200 J

Explanation:

The internal energy of a diatomic gas, such as N_2, is given by

U=\frac{5}{2}nRT

where

n is the number of moles

R is the gas constant

T is the absolute temperature of the gas

For the gas in this problem, we have:

n = 4.50 (number of moles)

R = 8.31 J/(mol·K) (gas constant)

T=253^{\circ} + 273 = 526 K (absolute temperature)

Substituting, we find:

U=\frac{5}{2}(4.50)(8.31)(526)=49,200 J

Learn more about ideal gases:

brainly.com/question/9321544

brainly.com/question/7316997

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#LearnwithBrainly

6 0
3 years ago
The diagram shows a positive charge moving in a magnetic field.
slavikrds [6]

By the right hand rule the magnetic force on the charge acts up

6 0
3 years ago
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William made one comment to an employee recently assigned to his team complimenting her on her dress. Later she was reprimanded
Ilya [14]

Answer:

C

Explanation:

William should fully in the investigation. If the only plausible evidence of sexual harassment  is a subtle compliment of an employee's choice or way of dressing. Such comments may be opinionated but are insufficient or a weak evidence for a sexual harassment case.    

5 0
3 years ago
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two ends of an inextensible string of length 12m are attached to points Aand B 1.2m apart,in the same horizontal plane.a mass 20
AlekseyPX
All forces must add up to zero. See pictures below.

7 0
3 years ago
Gaseous helium is in thermal equilibrium with liquid helium at 6.4 K. The mass of a helium atom is 6.65 × 10−27 kg and Boltzmann
chubhunter [2.5K]

Answer:

162.78 m/s is the most probable speed of a helium atom.

Explanation:

The most probable speed:

v_{mp}=\sqrt{\frac{2K_bT}{m}}

K_b= Boltzmann’s constant =1.38066\times 10^{-23} J/K

T = temperature of the gas

m = mass of the gas particle.

Given, m = 6.65\times 10^{-27} kg

T = 6.4 K

Substituting all the given values :

v_{mp}=\sqrt{\frac{2\times 1.38066\times 10^{-23} J/K\times 6.4 K}{6.65\times 10^{-27} kg}}

v_{mp}=162.78 m/s

162.78 m/s is the most probable speed of a helium atom.

4 0
3 years ago
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