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xxTIMURxx [149]
3 years ago
15

A block of mass m1=3.7kg on a smooth inclined plane of angle 30 is connected by a cord over a small frictionless pulley to a sec

ond block of mass m2=2.3kg hanging vertically. Calculate the acceleration of each block

Physics
1 answer:
kari74 [83]3 years ago
3 0

consider the forces on mass m₁ on the incline plane :

parallel to incline , force equation is given as

T - m₁ g Sin30 = m₁ a

T = m₁ g Sin30 + m₁ a                                       eq-1

consider the force on mass m₂ on the incline plane :

m₂ g - T = m₂ a  

T = m₂ g - m₂ a                                                  eq-2

Using eq-1  and eq-2

m₂ g - m₂ a = m₁ g Sin30 + m₁ a

inserting the values

(2.3 x 9.8) - 2.3 a = (3.7 x 9.8) Sin30 + 3.7 a

a = 0.74 m/s²


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Answer:

Plane will 741.6959 m apart after 1.7 hour                    

Explanation:

We have given time = 1.7 hr

So if we draw the vectors of a 2d graph we see that the difference in angles is   = 102^{\circ}-65.3^{\circ}=36.7^{\circ}

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