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3 years ago

14x 1 =63 square root equation

Mathematics

1 answer:

soldier1979 [14.2K]3 years ago

4 0

Add the one from the left to the 63 to get 64. Then divide both sides by 4 and get x^2=16. Take the square root of both sides to get x to equal 4.

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ASAP PLS Solve this exercise using the fact that the sum of the measures of the three angles of a triangle is 180°.In a triangl

Ira Lisetskai [31]

Answer:

80°, 40° and 60°

Step-by-step explanation:

Name the second angle X and the first angle to 2X (because it is twice the measure of angle number two) and the third angle to 20°+X (because it was 20° more than the second angle)

so we will have an equation of

180°=2x + x + (20°+x)

160°=4x

40°=x

so the second angle is 40° as it is represented by just one X

therefore the first angle which is twice the measure is 80° and the third angle which is 20° more is 60°. hope that helps!

8 0

3 years ago

Arithmetic sequences et sn} be an arithmetic sequence that starts with an initial index of 0. The initial term is 3 and the comm

navik [9.2K]

Answer:

(a) The value of $s_z$ is (z+1)(3-z).

(b) The next term in the sequence is -2.

Step-by-step explanation:

(a)

It is given that arithmetic sequence that starts with an initial index of 0.

The initial term is 3 and the common difference is -2.

$a_0=3$

$d=-2$

We need to find the value of $s_z$ .

$s_z=\sum_{n=0}^{n=z}(a+nd)$

where, a is initial term and d is common difference.

$s_z=\sum_{n=0}^{n=z}(3-2n)$

The sum of an arithmetic sequence with initial index 0 is

$s_n=\frac{n+1}{2}[2a+nd]$

where, a is initial term and d is common difference.

Substitute n=z, a=3 and d=-2 in the above formula.

$s_z=\frac{z+1}{2}[2(3)+z(-2)]$

$s_z=\frac{z+1}{2}[2(3-z)]$

$s_z=(z+1)(3-z)$

Therefore the value of $s_z$ is (z+1)(3-z).

(b)

The given arithmetic sequence is

7, 4, 1, ...

We need to find the term in the sequence.

In the given arithmetic sequence the first term is

$a=7$

The common difference of the sequence is

$d=a_2-a_1\Rightarrow 4-7=-3$

The first term is 7 and common difference is -3.

Add common difference in last given term, i.e., 1, to find the next term of the sequence.

$1+(-3)=1-3=-2$

Therefore the next term in the sequence is -2.

3 0

4 years ago

The function y = x * ln(x + e) has two distinct x intercepts. One is at x = a and the other is at x = b. The value of a + b is

Snezhnost [94]

As points, x-intercepts take the form $(x,0)$ , so to find the intercepts we can set $y=0$ and solve for $x$ .

$x\ln(x+e)=0\implies\begin{cases}x=0\\\ln(x+e)=0\end{cases}$

From the first equation alone, we already know that $x=0$ is a solution, which means one intercept is $(0,0)$ .

The second equation gives

$\ln(x+e)=0\implies e^{\ln(x+e)}=e^0\implies x+e=1\implies x=1-e$

so that the second intercept occurs at $(1-e,0)$ .

So if $a=0$ and $b=1-e$ , we have $a+b=1-e$ , giving C as the answer.

3 0

3 years ago

What is the answer?i need help I tried and it's not on the paper

Karolina [17]

You have to divide both sides by 2/3, and by doing that you'll get w= -5/4

7 0

3 years ago

Find the length of the third side. If necessary, write in simplest radical form

NARA [144]

Answer:

Step-by-step explanation:

Since this is a right triangle, we can use the Pythagorean theorem

a^2+b^2 = c^2 where a and b are the legs and c is the hypotenuse

a^2 + 10^2 = (5 sqrt(5))^2

a^2 +100 = 25(5)

a^2 +100 = 125

a^2 = 125-100

a^2 = 25

Taking the square root of each side

sqrt(a^2) = sqrt(25)

a = 5

6 0

3 years ago