Answer:
The velocity is 
Explanation:
From the question we are told that
The initial speed is 
The cross -sectional area of the first pipe is 
The cross -sectional area of the second pipe is 
Generally from continuity equation we have that
So
=> 
=>
Answer:
The mass of an object is a measure of the object's inertial property, or the amount of matter it contains. The weight of an object is a measure of the force exerted on the object by gravity, or the force needed to support it. The pull of gravity on the earth gives an object a downward acceleration of about 9.8 m/s2.
Answer:
v = rw
Explanation:
When an object is rolling continuously without slipping, then every angle it rotates through, is equal to a distance the perimeter has rotated.
If the object completes 10 revolutions and takes a particular time, let's say t to complete it. The angular distance would then be 20 π rad, while its angular velocity will be 20 π/t
The circumference will somehow translate to the distance it covers, which is 20πr, this means that the speed is 20πr/t
So, like the question asked, the linear speed compared to angular speed is
v : w
20πr/t : 20πt, which can be simplified to
r : 1
In essence, v = rw
Answer:
h' = 55.3 m
Explanation:
First, we analyze the horizontal motion of the projectile, to find the time taken by the arrow to reach the orange. Since, air friction is negligible, therefore, the motion shall be uniform:
s = vt
where,
s = horizontal distance between arrow and orange = 60 m
v = initial horizontal speed of the arrow = v₀ Cos θ
θ = launch angle = 30°
v₀ = launch speed = 35 m/s
Therefore,
60 m = (35 m/s)Cos 30° t
t = 60 m/30.31 m/s
t = 1.98 s
Now, we analyze the vertical motion to find the height if arrow at this time. Using second equation of motion:
h = Vi t + (1/2)gt²
where,
Vi = Vertical Component of initial Velocity = v₀ Sin θ = (35 m/s)Sin 30°
Vi = 17.5 m/s
Therefore,
h = (17.5 m/s)(1.98 s) + (1/2)(9.81 m/s²)(1.98 s)²
h = 34.6 m + 19.2 m
h = 53.8 m
since, the arrow initially had a height of y = 1.5 m. Therefore, its final height will be:
h' = h + y
h' = 53.8 m + 1.5 m
<u>h' = 55.3 m</u>
Answer:
m = 2,776.95 kg
Explanation:
given,
radius = 1.5 m
mass = 1.19 x 10⁴ Kg
constant speed, v = 1.4 m/s
Resistive force = 1105 N
density of sea water = 1.03 x 10³ kg/m³
Volume of vessel,
v = 14.14 m³
Upthrust,
U = ρ g V
U = 1030 x 9.8 x 14.14
U = 142729.16 N
Since the vessel is moving at a constant speed, the resultant force on it should equal zero.
downward acting forces = upward acting forces
Mg = U + resistive force
M x 9.8 = (142729.16+1105)
M=14676.95 Kg
Mass of water,
m = M - mass of vessel
m = 14676.95 Kg- 11,900 kg
m = 2,776.95 kg
