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DiKsa [7]
4 years ago
7

What are some drawbacks of electron microscopes? 3. If an object being viewed under the phase-contrast microscope has the same r

efractive index as the background material, how would it appear? +
Physics
1 answer:
gayaneshka [121]4 years ago
7 0

1. <u>Some drawbacks of electron microscopes:</u>

  • Price, size, repair, researcher learning and image artifacts arising from specimen preparation are the major drawbacks.
  • This form of magnification is a massive, burdensome, costly piece of equipment, highly sensitive to vibration and exterior magnetic field.
  • It must be held in an environment that is big enough to contain the microscope, as well as to secure and prevent any unwanted effect on the electrons.
  • Upkeep includes ensuring balanced voltage supplies, electromagnetic coil / lens currents and cool water circulation so that the specimens are not destroyed or damaged by the heat released during the electrons energization process.

2. If an object being viewed under the phase-contrast microscope has the same refractive index as the background material than "it would be difficult to see because the phase contrast microscope amplifies differences in the refractive index".

<u>Explanation:</u>

In order to improve the comparison of transparent and colorless specimens with the light microscopy pictures, thus phase contrast is used. This allows the visualization of cells and cell elements which would be hard to see using a standard light magnification. The phase comparison does not involve the destruction, fixation or staining of cells.

Due to diffraction and scattering phenomena which exist at the edges of these objects, large, extended specimens are also quickly visualized with phase contrast optical. As light transits through one medium to another, the velocity is changed in proportion to the variations in the refractive index between the two media. Therefore, the wave is either increased or decreased in velocity whenever a coherent light wave produced by the oriented microscope filament progresses via a phase specimen with a particular thickness and refractive index.

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One mole of an ideal gas does 2100 J of work as it expands isothermally to a final pressure 1.00 x 10^5Pa and volume of 0.025m^3
elena-s [515]

Answer:

(A) 0.004 m^3

(B) 48.11 K

Explanation:

Work, W = 2100 J

Pressure, P = 1 x 10^5 Pa

V2 = 0.025 m^3

(A) let the initial volume of the gas is V1.

W = P (V2 - V1)

2100 = 1 x 10^5 (0.025 - V1)

0021 = 0.025 - V1

V1 = 0.025 - 0.021

V1 = 0.004 m^3

Thus, the initial volume of the gas is 0.004 m^3.

(B) Let the temperature of the gas is T

Use ideal gas equation

P1 x V1 = n x R T

1 x 10^5 x 0.004 = 1 x 8.314 x T

T = 48.11 K

Thus, the initial temperature of the gas is 48.11 K.

4 0
3 years ago
what kinds of details does Kafka use to establish Gregor's life his metamorphosis into an insect. how do these familiar deta obj
irakobra [83]

Answer:

Kafka uses words to describe Gregor as a monster: gregor has many little legs, has a sort of shell that covers his body and so on.

Besides, the reactions of his family when they see him as the insect are of pure horror and disgust. This is why even one family member says that in that form, Gregor should simply be put down.

3 0
3 years ago
Tres personas, A, B, C, jalan una caja con ayuda de cuerdas cuya masa es despreciable. Si la persona A aplica −3 en dirección ho
Yuri [45]

Answer:

El valor de la fuerza que debe ejercer la persona C debe ser de -2 para que la caja esté en equilibrio físico.

Explanation:

Si la caja debe hallarse en equilibrio físico, entonces se debe satisfacer la siguiente ecuación:

F_{A} + F_{B} + F_{C} = 0 (1)

Si sabemos que F_{A} = -3 y F_{B} = 5, entonces el valor de la fuerza que debe ejercer la persona C debe ser:

F_{C} = -F_{A}-F_{B}

F_{C} = -(-3)-5

F_{C} = -2

El valor de la fuerza que debe ejercer la persona C debe ser de -2 para que la caja esté en equilibrio físico.

3 0
3 years ago
Please please help i need to finish this test
salantis [7]

Answer:

-4.4 m/s

Explanation:

Since the ball is thrown upward, we can ignore the horizontal velocity. This means that the vertical velocity is 25 m/s. The vertical acceleration is -9.8 m/s^2 (g). This means that after 3 seconds, the velocity would've decreased by 9.8 m/s^2 * 3 s. This is 29.4 m/s.

This should be subtracted from the initial velocity:

25 m/s - 29.4 m/s = -4.4 m/s

Hope this helps!

5 0
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Part of the Sun's energy that reaches the Earth's surface is absorbed by land and water as heat. The Earth's surface then releas
Feliz [49]
I think the correct answer is B- heat is trapped in the earth atmosphere 
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